Question

for p(x)= 192 + 21x^3 + 54x^2 - 3x^4 - 264x, use synthetic substitution to evaluate p(1), p(-2), and p(8)

Answer 1

The value of p(1), p(-2), and p(8) is 0, 744 and 0 respectively

What is polynomial function?

Given the function $p(x)= 192 + 21x^3 + 54x^2 - 3x^4 - 264x$

We are to get the following parameters:

$p(1)= 192 + 21(1)^3 + 54(1)^2 - 3(1)^4 - 264(1)\\p(1)=192+21+54-3-264\\p(1)=0$

For p(-2)

$p(-2)= 192 + 21(-2)^3 + 54(-2)^2 - 3(-2)^4 - 264(-2)\\p(-2)=192-168+216-24+528\\p(-2)=744$

For p(8)

$p(8)=192 + 21(8)^3 + 54(8)^2 - 3(8)^4 - 264(8)\\p(8)=192+10,752+3,456-12,288-2,112\\p(-2)=0$

Hence the value of p(1), p(-2), and p(8) is 0, 744 and 0 respectively

Learn more on polynomials here: brainly.com/question/4142886