What is the slope of a line parallel to the line whose equation is3x−4y=8?
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Answer:
Please, see the attached file.
Thanks.
Step-by-step explanation:
-5x-8y=40
This is a linear equation, and its graph is a right line, we only need two points, because by two points only goes trough only a right line:
1) For x=0→ -5(0)-8y=40
0-8y=40
-8y=40
Dividing both sides of the equation by -8:
-8y/(-8)=40/(-8)
y=-5
Point=(x,y)→Point=(0,-5)
2) For y=0→ -5x-8(0)=40
-5x-0=40
-5x=40
Dividing both sides of the equation by -5:
-5x/(-5)=40/(-5)
x=-8
Point=(x,y)→Point=(-8,0)
With these two points (0,-5) and (-8,0) we can draw the right line.
