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1 year ago

What is the slope of a line parallel to the line whose equation is3x−4y=8?

Mathematics

1 answer:

xxTIMURxx [149]1 year ago

7 0

The slope of the parallel line is 3/4

<h3>How to determine the slope?</h3>

The equation is given as:

3x - 4y = 8

Rewrite as:

4y = 3x - 8

Divide through by 4

y = 3x/4 - 2

A linear equation is represented as:

y = mx + b

Where m represents the slope

By comparison:

m = 3/4

Parallel lines have equal slope

Hence, the slope of the parallel line is 3/4

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<u>Step-by-step explanation:</u>

$\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}$

$\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}$

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