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Vikentia [17]
3 years ago
15

Which is equivalent to the following expression? (2x - 1)(x + 3)

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

2x2+5x−3

Step-by-step explanation:

Expand the polynomial using the FOIL method.

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Seven plus the product of two numbers
IceJOKER [234]

Step-by-step explanation:

this should show

7+ (xy)=

6 0
4 years ago
Help again... ASAP !<br><br> Show your workings!<br><br> Irrelevant answers will be reported!
Pie
<h2>This is your answer :</h2>

<h3>L (6,-6)</h3>

3 0
3 years ago
Decide whether the pair of ratios form a proportion 15/12=4.5/3.6
Hitman42 [59]

Answer: Yes they form a proportion. The given equation is a true equation.

==========================================

Explanation:

The idea is that if we have

a/b = c/d

then that it is the same as

a*d = b*c

This is known as cross multiplication. We'll use this rule to get

15/12 = 4.5/3.6

15*3.6 = 12*4.5

54 = 54

We got the same value on both sides, meaning that the last equation is true. Consequently, it means the first equation is true as well (all three equations are true).

--------

You could also use your calculator to see that

15/12 = 1.25

4.5/3.6 = 1.25

showing that 15/12 = 4.5/3.6 is a true equation and the ratios form a proportion.

4 0
4 years ago
Read 2 more answers
Choose the correct answer 1 1/12 - 7/10 greater than half or less than half​
CaHeK987 [17]

Answer:

less than half

Step-by-step explanation:

13/12 - 7/10 = 23/60

5 0
3 years ago
Simplify 1- cos^2 Θ / cos^2 Θ<br><br> Answers<br><br> sin2 θ<br><br> cos2 θ<br><br> tan2 θ<br><br> 1
Tems11 [23]

Answer:

<h3><u /></h3>

<u>Trigonometric identities</u>

<u />

\large \begin{aligned}\cos^2 \theta + \sin^2 \theta & = 1\\\implies \quad \quad \sin^2 \theta & = 1 - \cos^2 \theta\\\\\tan \theta=\dfrac{\sin \theta}{\cos \theta} \end{aligned}

Therefore, using the <u>identities</u>, the given expression can be <em>simplified</em> as follows:

\large\begin{aligned}\implies \dfrac{1- \cos^2 \theta}{\cos^2 \theta} & = \dfrac{\sin^2 \theta}{\cos^2 \theta}\\\\& = \tan^2 \theta\end{aligned}

3 0
2 years ago
Read 2 more answers
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