the Highest common factor of 130,260,390 = 130
130 = 2⋅5⋅13
260 = 2⋅2⋅5⋅13
390 = 2⋅3⋅5⋅13
Common multipliers (130; 260; 390): 2, 5, 13
Now to find the highest Common factor you need to multiply the common factors
Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130
Answer:
Although I'm not entirely sure of the question (sorry lol), any ratio that is 1.5:2 , 6:8 , 9:12 , 12:18 etc would be equivalent to 3 to 4.
Step-by-step explanation:
If you divide both 3 and 4 by 2 you'd wind up with 1.5 ( 3 ) and 2 ( 4 ). When multiplying, you'd get 3x2 = 6 and 4x2=8, 3x3 = 9 and 4x3 = 12 and so on.
Answer:
two and a half
Step-by-step explanation:
Answer:
Total number of students = 50 students.
Step-by-step explanation:
Total number of books = number of books * frequency
1 * 3 = 3
2 * 5 = 10
3 * 12 = 36
4 * 25 = 100
5 * 4 = 20
6 * 1 = 6
Total number of books = 3 + 10 + 36 + 100 + 20 + 6
Total number of books = 175 books.
Now, to find the total number of students;
Total number of students = summation of frequency
Total number of students = 3 + 5 + 12 + 25 + 4 + 1
Total number of students = 50 students.
