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oee [108]
2 years ago
9

HELPPPPPP PLLSLLSLSLLSSS!!!

Mathematics
1 answer:
ELEN [110]2 years ago
6 0

Answer:

It is better to buy the <u>10-ounce box for $1.95</u>

Step-by-step explanation:

1.) Set up a ratio to represent this problem.

Ounces : Price

10 : 1.95

14 : 2.81

2.) Find the unit price for the first ratio.

10 : 1.95

/10  /10

1 : 0.195

This means that a one-ounce box of cereal will cost $0.12

3.) Find the unit price for the second ratio.

14 : 2.81

/14  /14

1 : 0.20071428571

This means that a one-ounce box of cereal will cost $0.20

4.) Compare prices

$0.12 < $0.20

Therefore, it is better to buy the 10-ounce box for $1.95.

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(7,-4);
olga_2 [115]

Literally just plug it in

6(7) + 5(-4) - 42 = 0

42 -20 -42 = 0

-20 = 0

Not a solution.

8 0
3 years ago
Grayson evaluated 4x2 + 2y for x = 3 and y = 2.
guajiro [1.7K]
Grayson did not simplify the question
5 0
3 years ago
What is 7/12 divided by 36?
Georgia [21]
7/12 = 0.84
0.84/36 = 0.0233·
3 0
3 years ago
TRY IT Solve and support your thinking
iris [78.8K]

Answer:

45 hihihihihihihihihihihihih

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
wel

Answer:

z=\frac{15\sqrt{3}}{2}

Step-by-step explanation:

In leftmost triangle:

opposite side =y

adjacent=a

now, we can use trig formula

tan(60)=\frac{y}{a}

now, we can solve for y

y=atan(60)

In rightmost triangle:

adjacent=b

opposite=y

a+b=15

b=15-a

now, we can use trig formula

tan(30)=\frac{y}{15-a}

now, we can solve for y

y=(15-a)tan(30)

now, we can set them equal

and then we can solve for a

atan(60)=(15-a)tan(30)

\sqrt{3}a\cdot \:3=\frac{\sqrt{3}\left(15-a\right)}{3}\cdot \:3

4\sqrt{3}a=15\sqrt{3}

a=\frac{15}{4}

now, we can find b

b=15-\frac{15}{4}

b=\frac{45}{4}

now, we can use trig formula

cos(30)=\frac{b}{z}

now, we can find z

z=\frac{\frac{45}{4}}{cos(30)}

we can simplify it

and we get

z=\frac{15\sqrt{3}}{2}


4 0
3 years ago
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