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Mazyrski [523]
2 years ago
10

A sealed flask initially contains pure nitrogen dioxide gas (NO,). Over time, the nitrogen dioxide forms dinitrogen tetroxide ga

s (N,O.). The graph below shows the relative amounts of (NO,) and (N20.) over time. What is true about the time indicated by the blue arrow?
Chemistry
1 answer:
Sveta_85 [38]2 years ago
7 0

This problem is providing information about the equilibrium reaction whereby nitrogen dioxide gas produced dinitrogen tetroxide gas as shown on the attached picture and the following chemical equation:

NO₂ (g)  ⇄ N₂O₄ (g)

In such a way, we can consider the given choices to reason the following:  the blue arrow is pointing out the arrival to the equilibrium condition for the reaction, a point in which the rate of the forward reaction (formation of N₂O₄) is equal to the rate of the reverse reaction (formation of NO₂), because the molecules will fluctuate to the same relative amounts defined by the equilibrium constant.

Therefore the answer will be the first one on the attached file, which can vary on your online homework format.

It is important to note that the reactant is not used up at any point of the graph (concentration drops to 0) and also, the activation energy cannot be analyzed with this sparse information.

Learn more:

  • (equilibrium concentrations) brainly.com/question/7949757

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How many milligrams of product can be produced from the complete Diels-Alder reaction of 180. mg of anthracene and 100. mg of ma
ZanzabumX [31]

Answer: It will be produced 276,3 mg of product

Explanation: The reaction of anthracene (C14H10) and maleic anhydride (C4H2O3) produce a compound named 9,10-dihydroanthracene-9,10-α,β-succinic anhydride (C18H12O3), as described below:

C14H10 + C4H2O3 → C18H12O3

The reaction is already balanced, which means to produce 1 mol of C18H12O3 is necessary 1 mol of anthracene and 1 mol of maleic anhydride.

1 mol of C14H10 equals 178,23 g. As it is used 180 mg of that reagent, we have 0,001 mol of anthracene. With it, the reaction produces 0,001 mol of C18H12O3.

As 1 mol of C18H12O3 equals 276,3 g, the mass produced is 276,3 mg.

3 0
3 years ago
A salt bridge: Question 3 options: provide a pathway through which the electrons travel from the cathode to the anode. provide a
Vesnalui [34]

Answer:

The correct option is: provide a source of counterions to prevent the build-up of charge at both the cathode to the anode.

Explanation:

A salt bridge is a U-shaped glass tube that is used in a voltaic cell or galvanic cell to connect the oxidation and reduction half-cells and complete the electric circuit.

<em>It allows the ions to pass through it, thus preventing the accumulation of charge on the anode and cathode as the chemical reaction proceeds.</em>

<u />

Therefore, the correct option is: <u>provide a source of counterions to prevent the build-up of charge at both the cathode to the anode.</u>

5 0
4 years ago
What type of matter is salt water?
algol13
Salt water is a Homogeneous Mixture......
8 0
4 years ago
PLEASE HELP!! WILL MARK BRAINLIEST
Andrew [12]

Answer:

The answer to your question is below

Explanation:

                                         Trial 1                   Trial 2

mass of Mg                      0.255 g                0.353 g

mass of MgO                   0.418 g                 0.576 g

Chemical reaction

                                2Mg(s)    +  O₂(g)     ⇒   2MgO(s)

Question 1.

Atomic mass of Mg = 24.31 x 2 = 48.62 g

Molecular mass of MgO = 2(24.31 + 16) = 80.62 g

Trial 1

                          48.62 g of Mg ----------------- 80.62 g of MgO

                          0.255 g            ----------------   x

                          x = (0.255 x 80.62)/48.62

                          x = 0.422 g of MgO

Trial 2                48.62 g of Mg ----------------- 80.62 g of MgO

                          0.353 g            ----------------   x

                          x = (0.353 x 80.62)/48.62

                          x = 0.585 g of MgO

Question 2

Trial 1          

Percent yield = 0.418/0.422 x 100 = 99%

Trial 2

Percent yield = 0.576/0.585 x 100 = 98.5%

Question 3

Average = (99 + 98.5)/2

              = 98.75%

3 0
3 years ago
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love history [14]

Answer:

They all end up in the oceon

Explanation:

5 0
3 years ago
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