Answer:
2.06 aluminium ions in the sample, due to the chemical formula.
Explanation:
<u>Answer:</u> The 
for the reaction is -104.7 kJ.
<u>Explanation:</u>
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.
The chemical equation for the formation of propane follows:
The intermediate balanced chemical reaction are:
(1) 
(2) 
( × 3)
(3) 
( × 2)
The expression for enthalpy of the reaction follows:
![\Delta H^o_{rxn}=[1\times (-\Delta H_1)]+[3\times \Delta H_2]+[2\times \Delta H_3]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B1%5Ctimes%20%28-%5CDelta%20H_1%29%5D%2B%5B3%5Ctimes%20%5CDelta%20H_2%5D%2B%5B2%5Ctimes%20%5CDelta%20H_3%5D)
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times (-(-2043))+(3\times (-393.5))+(2\times (-483.6))]=-104.7kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%28-%28-2043%29%29%2B%283%5Ctimes%20%28-393.5%29%29%2B%282%5Ctimes%20%28-483.6%29%29%5D%3D-104.7kJ)
Hence, the for the reaction is -104.7 kJ.
Answer:
3+
Explanation:
i looked up the answer :)
The percentage composition of Nitrogen in the compound is 35.71%
<h3>How to determine the mole of nitrogen</h3>
- Volume (V) = 100 mL = 100 / 1000 = 0.1 L
- Pressure (P) = 700 mmHg
- Temperature (T) = 250 K
- Gas constant (R) = 62.364 torr.L/Kmol
- Number of mole (n) =?
Using the ideal gas equation, the mole of nitrogen can be obtained as follow
PV = nRT
n = PV / RT
n = (700 × 0.1) / ( 62.364 × 250)
n = 0.00448 mole
<h3>How to determine the mass of nitrogen</h3>
- Mole of nitrogen = 0.00448 mole
- Molar mass of nitrogen = 28 g/mol
- Mass of nitrogen = ?
Mass = mole × molar mass
Mass of nitrogen = 0.00448 × 28
Mass of nitrogen = 0.125 g
<h3>How to determine the percentage of nitrogen</h3>
- Mass of nitrogen = 0.125 g
- Mass of compound = 0.35 g
- Percentage of nitrogen =?
Percentage = (mass of element / mass of compound) × 100
Percentage of nitrogen = (0.125 / 0.35) × 100
Percentage of nitrogen = 35.71%
Learn more about mass composition:
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