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kirza4 [7]
3 years ago
10

Why is it important to know the relationships between categorical variables?

Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer: it is important to know the relationships between both to make sure you will use the correct way to use each and to explain a problem.

Step-by-step explanation:

A pie chart or bar graph might be used to display the distribution of a categorical variable while a boxplot or histogram might be used to picture the distribution of a measurement variable.

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svlad2 [7]

Answer: I would say try and use your 150 stars you’ll save more money for that day and earn more stars.

Step-by-step explanation:Hope this helps!

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3 years ago
What is 3 4/5 rounded to the nearest half
Sphinxa [80]
3 1/2 or 7/2
keep the 3 yards and round the 4/5 to half a yard or 1/2 and just in case turn into a improper fraction
5 0
2 years ago
Read 2 more answers
4. Given the data below, where X is the independent variable and Y is the dependent variable. If you
oksian1 [2.3K]
The answer is A, look at the difference between 0 and 15 (15) and the difference between 5 and 10 (5) then divide them 5/15.
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3 years ago
Given that A, O &amp; B lie on a straight line segment, evaluate <br>x<br>.​
Afina-wow [57]

Answer:

Step-by-step explanation:

It is the same way:

       we know that

if A , O and B lie on a straight line segment

then

∡AOY+∡YOZ+∡ZOB=180°

so

3x+x+x=180-----> 5x=180--------> x=180/5--------> x=36°

the answer is

x=36°

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4 0
3 years ago
A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st
shutvik [7]

Answer:

Equation of movement y(t)

y(t)=sin(10t-\pi/2)

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

A=1\,inch

The period depends on the mass and the spring constant.

The formula for the period is:

T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s

The model y(t) for the movement of the mass-spring system is

y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)

8 0
3 years ago
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