The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).
<h3>How to find an approximate solution of a one-variable equation</h3>
The solution of the equation is between x = 4 and x = 5. Now we begin by evaluating each side of the expression (f(x) = x² - 5 · x + 4, g(x) = 2 / (x - 1)) at the average of x = 4 and x = 5.
x = (4 + 5) / 2
x = 4.5
f(4.5) = 4.5² - 5 · 4.5 + 1
f(4.5) = - 5 / 4
g(4.5) = 2 / (4.5 - 1)
g(4.5) = 4 / 7
The solution of the equation is between x = 4.5 and x = 5, then we evaluate at the average:
x = (4.5 + 5) / 2
x = 4.75
f(4.75) = 4.75² - 5 · 4.75 + 1
f(4.75) = - 3 / 16
g(4.75) = 2 / (4.75 - 1)
g(4.75) = 8 / 15
The solution of the equation is between x = 4.75 and x = 5, then we evaluate at the average:
x = (4.75 + 5) / 2
x = 4.875
f(4.875) = 4.875² - 5 · 4.875 + 1
f(4.875) = 25 / 64
g(4.875) = 2 / (4.875 - 1)
g(4.875) = 16 / 31
The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).
To learn more on successive approximations: brainly.com/question/27191494
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Answer:
35.9 grams
Step-by-step explanation:
We use the formula:
Where
q is heat released
m is mass
C_p is the constant 2.44
ΔT is change in temperature
We put the info in the formula and solve for m (mass):
The mass of ethanol is 35.9 grams
Answer:
Increasing a number by 5% and then by 20% is the same as increasing the original number by 26%.
Step-by-step explanation:
Take a number, x.
Now increase it by 5%.
1.05x
Now increase it by 20%.
1.2 * 1.05x = 1.26x
1.26x = 126% of x = 100% of x + 26% of x
100% of x is the same as x, so it is the same as the original x.
The increase is 26% of the original number.
Increasing a number by 5% and then by 20% is the same as increasing the original number by 26%.
Answer: D
"Separating the students on the list into boys and girls and choosing a sample from each group that is proportional to the size of the group."
Step-by-step explanation:
You are sampling an equal amount of boys and girls since your getting an equal sample of each gender. (Not random)
