B. ASA
FGH = IHG
Please correct me if I'm wrong!! :)
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
f(x) = (x+2) (x+2)^3 (x-1) (x-6)
Step-by-step explanation:
The first zero, -2, corresponds to the factor x+2 of the polynomial.
Given that this zero, -2, has multiplicity 3, (x+2)^3 represent the first three factors of the polynomial.
The next factor stems from the zero 1: (x-1).
The next 6 factors stem from the zero 6: (x-6).
Writing the polynomial in factored form, we get:
f(x) = (x+2) (x+2)^3 (x-1) (x-6)
