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kozerog [31]
3 years ago
9

Jack was planting a tree. He was to dig a hole that was 3 feet deep for every 5 feet of tree height. How deep should he dig the

hole for a tree that is 17 feet high
Mathematics
2 answers:
nlexa [21]3 years ago
4 0
Jack was planting a tree. He was to dig a hole that was 3 feet deep for every 5 feet of tree height. How deep should he dig the hole for a tree that is 17feet high. 

Calculations 

\frac{DEEP}{HIEGHT} 

Cross multiplication

\frac{3 DEEP}{5 HIEGHT} = \frac{x}{13} 

5x = 2 x 13 

Divide by 5 to isolate x

\frac{5x}{5} = \frac{51}{5} 

x = 10.2 

Answer = 10.2 
Inga [223]3 years ago
4 0
5/3=1.66666... so thats the ratio so 17/ 1.6666666... would equal 10.2 which is your answer.
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Please answer the question above.
kenny6666 [7]

Answer:

5.3!

Step-by-step explanation:

( in case you need work ) the angles are congruent so you set them equal to each other!

6x+12=9x-4

you then get 16=3x then divided its 5.3!

8 0
3 years ago
Rectangle Given:1=15 m, w=6m,A=​
sashaice [31]

Answer:

90m^2 and 144 m^2

Step-by-step explanation:

Given :

Length of the rectangle (l)=15m

Width of the rectangle (w)= 6 m

Area of the rectangle can be calculated as :

A=l*w\\A=(15)(6)\\A=90 m^2

Now,

Side of square (s)=12 m

Area of the square can be find:

A=s^2\\A=12^2\\A=144 m^2

6 0
2 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
Petrina had a piece of red ribbon that measured 2.4 m long. she also had a piece of blue ribbon which was 7 8 m long. what was t
katen-ka-za [31]

The total length of red and blue ribbons is 10.2 m.

Given that, the length of the red ribbon =2.4 m and the length of the blue ribbon =7.8 m.

<h3>How to add two decimals?</h3>

Adding decimals is similar to the usual addition of whole numbers. We know that a decimal number is a number with a whole number part and a fractional part which is separated by a decimal point.

Now, the length of the red ribbon + the length of the blue ribbon=2.4+7.8

=10.2 m

Therefore, the total length of red and blue ribbons is 10.2 m.

To learn more about the addition of decimals visit:

brainly.com/question/17612968.

#SPJ4

7 0
2 years ago
Find the following angles<br>​
Serga [27]

Answer:

Downwards ↓

Step-by-step explanation:

a°=90° (right angle)

c°=45° (diagonal)

b°=180-63 (angles on a straight line)

=117°

3 0
3 years ago
Read 2 more answers
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