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kap26 [50]
2 years ago
6

You work part time at a book store and get paid $9.16 per hour. Last month you worked

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
8 0

Multiply hourly rate by total hour:

$9.16 x 7.28 = $66.68

Answer: $66.68

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Theo started to solve the quadratic equation (x + 2)^2 – 9 = –5. He added 9 to both sides and the resulting equation was (x + 2)
Sliva [168]
When we take the square root of each side, the equation would become:
abs (x+2) = 2
⇒ x+2 = <span>±2.

The final answer is </span><span>x + 2 = ±2.
</span>
Hope this helps~



6 0
3 years ago
Read 2 more answers
Plz help meh... i need it asap
kap26 [50]

Answer:

y=x

Step-by-step explanation:

In this graph, all the x values are the same as the y values

y=x

(1,1)

(2,2)

(3,3)

(4,4)

etc..

6 0
2 years ago
What is the slope of a line if X intercept is three and Y intercept is five
Ber [7]

Answer:

y=5x-15

Step-by-step explanation:

4 0
3 years ago
A manufacturing process makes rods that vary slightly in length but follow a normal distribution with mean length 25 cm and stan
Galina-37 [17]

Answer:

The probability of randomly selecting a rod that is shorter than 22 cm

P(X<22)  = 0.1251

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given mean of the Population = 25cm

Given standard deviation of the Population = 2.60

Let 'x' be the random variable in normal distribution

Given x=22

Z = \frac{x-mean }{S.D} = \frac{22-25}{2.60} = -1.15

<u><em>Step(ii):</em></u>-

The probability of randomly selecting a rod that is shorter than 22 cm

P(X<22) = P( Z<-1.15)

             = 1-P(Z>1.15)

             =  1-( 0.5+A(1.15)

             =  0.5 - A(1.15)

             = 0.5 - 0.3749

             = 0.1251

The probability of randomly selecting a rod that is shorter than 22 cm

P(X<22)  = 0.1251

7 0
3 years ago
PLEASE HELP!!! 15 PTS!!
kherson [118]

Answer:

\large\boxed{C.\ (2,\ -45^o)}

Step-by-step explanation:

Regular coordinates (x, y)

Polar coordinates (r, φ)

r=\sqrt{x^2+y^2}\\\\\psi=\arctan\frac{y}{x}

We have the point

(\sqrt2,\ -\sqrt2)

Substitute:

r=\sqrt{(\sqrt2)^2+(-\sqrt2)^2}=\sqrt{2+2}=\sqrt4=2\\\\\psi=\arctan\left(\frac{-\sqrt2}{\sqrt2}\right)=\arctan(-1)=-45^o

6 0
3 years ago
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