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Maurice wants to create a set of elliptical flower beds. To do this, he first plots the location of the two fruit trees on his graph.
Maurice has to use the equation a^2-b^2=c^2. We know that c=3, and because we need 1 more number to solve for b, I made a=6. 6^2-b^2=3^2. 36-b^2=9. b^2=27. b=5.196
<span>Next, to create the equation, we substitute what we know into the equation x^2/a^2 + y^2/b^2=1 and get x^2/36 + y^2/27=1. Johanna wants to create some hyperbolic flower beds.
We already know that c=3 so this time I decided a=1. 3^2=1^2+b^2. 9=1+b^2. 8=b^2. b=2.828
Next, to create the equation, we substitute what we know to the equation x^2/a^2 - y^2/b^2 = 1. x^2/1^2 - y^2/2.828^2 = 1. </span>
A and H both have line symmetry
Answer:
<h2><em>
D. (-7, 3)</em></h2>
Step-by-step explanation:
The standard form of a point slope equation of a line is expressed as shown;
y-y₀ = m(x-x₀) where;
m is the slope of the line
(x₀, y₀) is the coordinate of the point that lies in the line.
Comparing the standard equation given with the equation in question
y - 3 = 4(x + 7) to get the point on the line we will have;
y₀ = 3 and -x₀ = 7
for -x₀ = 7;
multiply both sides with a minus sign
-(-x₀) = -7
x₀ = -7
<em>Hence the coordinate of the point required (x₀, y₀) is (-7, 3).</em>
