Answer:
This is your work so i cant do it but I can give you a hint divide both the numerator and deomonator to get simplified form
Step-by-step explanation:
1) 3/4-1/4=2/4=1/2
2)3/10-1/10=2/10=1/5
we have the number
![6-\sqrt[]{-40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B-40%7D)
Remember that
i^2=-1
so
substitute
![6-\sqrt[]{(i^2)40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B%28i%5E2%2940%7D)
![6-2i\sqrt[]{10}](https://tex.z-dn.net/?f=6-2i%5Csqrt%5B%5D%7B10%7D)
therefore
the real part is 6
the imaginary part is -2√10
Answer:
6x ≥ 3 + 4(2x - 1)
⇔ 6x ≥ 3 + 8x - 4 => remove the parentheses
⇔ 6x - 8x ≥ 3 - 4
⇔ -2x ≥ -1
⇔ 2x ≤ 1 (or 1 ≥ 2x)
⇔ x ≤ 1/2
⇔ x ≤ 0.5
The answer for the question should be:
1 ≥ 2x
6x ≥ 3 + 8x – 4
and the first graph.
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