They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:
y=150-600t x=200-800t
By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:
d^2=y^2+x^2, using y and x from above
d^2=(150-600t)^2+(200-800t)^2
d^2=22500-180000t+360000t^2+40000-320000t+640000t^2
d^2=1000000t^2-500000t+62500
d=√(1000000t^2-500000t+6250)
So the rate of change is the derivative of d
dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)
dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)
So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...
...
To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...
1000000t^2-500000t+62500=0
6250(16t^2-8t+1)=0
6250(16^2-4t-4t+1)=0
6250(4t(4t-1)-1(4t-1))=0
6250(4t-1)(4t-1)=0
6250(4t-1)^2=0
4t-1=0
4t=1
t=1/4 hr
Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)
Answer:
C. F(x) = x²
Step-by-step explanation:
"Quadratic" means "second degree". The only function with an exponent of 2 is choice C.
Answer:
- 120
Step-by-step explanation:
call x is the number you want to find
- (3/4 )x + 3
= (2/3)x - 6 - (3/4)x + (7/2) = (2/3)x - (13/2)
- (3/4)x - (2/3)x = - (13 /2) - (7/2)
- (1/12)x = -10
- x = -10 / (1/12) = -120
1-kilometers or miles
2-what is the size of the jug? (If is smal use ml if is large liters
3-grames ou onces
4onces or kilograms
