Answer:
A) 
Step-by-step explanation:
Given expression:
To factor the given expression completely.
Solution:
In order to factor the expression, we will factor in pairs.
We will factor the G.C.F of the terms in the pairs.
G.C.F. of 
and 
can be given as:
Thus, G.C.F. = 
G.C.F. of 
and 
can be given as:
Thus, G.C.F. = 
The expression after factoring the G.C.F. pairs is given as:
Taking G.C.F. of the whole expression as 
is a common term.
The expression is completely factored.
We are given that
An ion has a charge of +7
and a neutral has charge always 0
so, change is charge = ion charge - neutral change
so, we can plug values
change is charge = +7 -0
change is charge = 7
so, option-C..................Answer
9 or 27 not quite sure gl
Y=3x^2-15x-x+5=3x^2-16x+5
(3x-1)(x-5)
-5(x^2+12+36)+22=-5x^2-24-180+22=
=-5x^2-182
Answer:
The first equation should be multiplied by 9 and the second equation by −4
Step-by-step explanation:
Given the simultaneous equation
First Equation: 5x − 4y = 28
Second equation: 3x - 9y = 30
In order to eliminate y, we must make the coefficient of x in both expression to be equal.
To do that the first equation should be multiplied by 9 (negative value of the coefficient of y in equation 2)and the second equation by -4( (coefficient of y in equation 1)
