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3 years ago

What is the difference in simplest terms of 3/4 - 1/3

Mathematics

1 answer:

GuDViN [60]3 years ago

6 0

Answer:

5/12

Step-by-step explanation:

can't be anymore simplified, it already is

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From a sample of 50 incinerators in a major city. of the 50 samples, only 18 met an environmental standard for the concentration

yuradex [85]

Yes. since half of 50 is 25 it is correct to say that 18 is less than half

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3 years ago

A package of fish weighs 2.5 pounds. The price is $3.50 per pound. What is the price of this package?

Wewaii [24]

Answer:

$8.75

Step-by-step explanation:

If you do

$3.50 x 2.5 you get

$8.75

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3 years ago

What is 6/7 as a decimal

Klio2033 [76]

0.86 if it is rounded.

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3 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

gavmur [86]

The summary of the ruler placement postulate is given as:

there is a one-to-one correspondence between the set of points on the line and the set of real numbers, and.
the distance between two points equals the absolute value of the difference between the corresponding numbers.

<h3>What is the ruler placement postulate?</h3>

This states that the points of a line can be matched and correspond to a set of points on the line and the set of real numbers,

Therefore, based on the fact that your question is incomplete, a general overview of the ruler placement postulate is given to give you a better understanding of the concept.

Read more about the ruler placement postulate here:

brainly.com/question/25097538

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4 0

2 years ago

Use the Normal model N(1133,78) for the weights of steers.

Rudiy27

Answer:

Step-by-step explanation:

Let $X\sim N(1133, 78)$ .

Here, the mean is 1133 and standard deviation is 78.

Since we don't have the table for N(1133, 78), so we use the standard table for N(0,1),

All we have to do is find, within the table the specific percentile.

now to find (42nd percentile) 0.42 in the normal table N(0,1) and extract the number on the row and column.

$P(X\leq x)=0.42$

Using: $Z=\frac{X-\mu}{\sigma}$ where $\mu$ is the mean and $\sigma$ is the standard deviation.

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.42$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.42$

Now, using Standard Normal table to find the value of z- score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z.

i.e, $z= -0.20$

Now, putting this value in $z=\frac{x-1133}{78}$ , to find x;

$\frac{x-1133}{78}=-0.20$

On Simplify, we get;

$x=1,117.4$ pounds

Similarly, find the weight for 91st percentile.

Follow the same steps that we have done in part (a),

$P(X\leq x)=0.91$ or

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.91$

⇒ $P(Z \leq \frac{x-1133}{78})=0.91$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.91$

Now, use normal table value to find the z-score;

Usually, tables are set up as the probability that a number, z is less than or equal to Z

we have, z= 1.34

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=1.34$

On simplify, we get

x= 1,237.52 pounds

the interquartile range (IQR)=3rd Quartile - 1st quartile

First find the 1st quartile:

$P(\frac{X-1133}{78} \leq \frac{x-1133}{78})=0.25$

⇒ $P(Z \leq \frac{x-1133}{78})=0.25$

let $z=\frac{x-1133}{78}$

then, we have

$P(Z\leq z)=0.25$

Now, we use normal table to find that z=-0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=-0.675$

On simplify, we get

x= 1,080.35 pounds

Similarly, for third quartile

By symmetry z=0.675

putting the z value in $z=\frac{x-1133}{78}$ we get,

$\frac{x-1133}{78}=0.675$

On simplify, we get

x= 1,185.65 pounds

then, IQR = 1185.65 -1080.35=105.3 pounds

7 0

3 years ago