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2 years ago

Evaluate the expression y2 when y=2.5 .

Mathematics

1 answer:

kkurt [141]2 years ago

5 0

Answer:

5 but if it's supposed to be squared it's 6.25

Step-by-step explanation:

2.5*2=5

if supposed to be squared then

2.5*2.5=

6.25

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Alan, Bianca, and Charles are counting in turn. Alan says "one," Bianca says "two," and Charles says "three." Then it's Alan's t

timama [110]

Bianca would say fifty nine

8 0

3 years ago

Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre

Lera25 [3.4K]

Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is $\$100.$

The amount deposited in February is $1\$00\times 3= \$300.$

The amount deposited in March is $\$300\times 3= \$900.$

The amount deposited in April is $\$900\times 3= \$2\700.$

The amount deposited in May is $\$2\,700\times 3= \$8\,100.$

The amount deposited in June is $\$8\,100\times 3= \$24\,300.$

Step 2

The next step is to add up all the money that was deposited into the account. This calculation is shown below,

$\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400$

5 0

3 years ago

Read 2 more answers

04. A school band charges a $160 flat fee plus $40 an hour to play.

Degger [83]

Answer:

Step-by-step explanation:

$\frac{320-160}{40}=\frac{160}{40}=4$

School band played for 4 hours.

3 0

3 years ago

Which is the value of this expression when a=5 and k=-2

Zinaida [17]

Answer:

Option C is correct.

Step-by-step explanation:

We are given the expression:

$(\frac{3^2a^{-2}}{3a^{-1}})^k$

The value of a =5 and k = -2

Putting the values and solving

$=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}$

Option C is correct.

3 0

3 years ago

Define a substitution method to solve the followingsysten of equation of y=2x-3, x+y=1

Ivan

I will solve you system by substitution

y = 2x - 3 ; x + y = 1

→Step 1: Solve y = 2x - 3 for y

→Step 2: Substitute 2x - 3 for y in x + y = 1:

x + y = 1

x + 2x- 3 = 1

3x - 3 = 1 (Simplify both sides of the equation)

3x - 3 + 3 = 1 + 3 (Add 3 both sides)

3x = 4

3x ÷ 3 = 4 ÷ 3 (Divide each side by 3)

x = 4/3

→Step 3: Substitute 4/3 for x in y = 2x - 3:

y = 2x - 3

y = 2 (4/3) -3

y = -1/3 (Simplify both sides of the equation)

Answer:

x = 4/3 and y = -1/3

∫Hope that helps∫

7 0

3 years ago