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3 years ago

What is the apparent solution to the system of equations?

Mathematics

1 answer:

Radda [10]3 years ago

6 0

Y= 12 - 2x-2x-2x-2x so it will be Ben Ben this d in your mouth ah ah 12=2x

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Write 5040 in scientific notation

skelet666 [1.2K]

5.04 × 10³

This is the scientific notation.

5 0

3 years ago

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A conductor possesses a positive charge of 3.2x 10-19 C. How many electron does it have in excess or deficit (e = 1.60 x 10-19C)

LenKa [72]

The no of electrons it have in deficit=1.60

Given:

Charge possessed by a conductor = $3.2 \times 10^{-19} C$

Charge of an electron= $1.6 \times 10^{-19} C$

To find:

Amount of electrons in excess or deficit

Step by Step Explanation:

Solution;

Formula used for calculating electrons in excess or deficit is given as

Electrons in excess or deficit= Normal electron charge- Charge of the conductor

Also we know Charge of Conductor $=3.2 \times 10^{-19} C$ and Electron charge $=1.6 \times 10^{-19} C$

Substitute these values in the above equation we get

Electrons in excess or deficit= $1.60 \times 10^{-19} \mathrm{C}-3.2 \times 10^{-19} \mathrm{C}$

= -1.60

Result:

Hence, it has a deficit of 1.60 electrons.

3 0

3 years ago

Trisha is taking care of the Han family's dogs.The Hans leave 7 cans of dog food for the 3days they'll be away.How much food wil

Verdich [7]

Answer:

2 1/3 food

Step-by-step explanation:

Cans of dog food = 7

Number of days = 3

If Trisha feeds them an equal amount each day, then each day the dogs will get:

$\frac{7}{3}=2\frac{1}{3}$ food

7 0

3 years ago

45 +2.50m = 3.75m what is the answer

zhannawk [14.2K]

m = 36

Work

45 + 2.50m = 3.75m

-3.75m -3.75m

45 - 1.25m = 0

- 45 - 45

-1.25m = -45

-1.25 -1.25

m = 36

3 0

3 years ago

I can’t figure this out

RSB [31]

Answer:

$\large{60^o\to\dfrac{19\pi}{3}\\\\288^o\to\dfrac{18\pi}{5}\\\\315^o\to\dfrac{23\pi}{4}\\\\80^o\to\dfrac{22\pi}{9}}$

Step-by-step explanation:

$\text{The formula of conversion of degrees to radians:}\ \dfrac{\theta \pi}{180}\\\\360^o=2\pi\\\\60^o=\dfrac{60\pi}{180}=\dfrac{\pi}{3}\qquad\dfrac{19\pi}{3}=6\pi+\dfrac{\pi}{3}=\dfrac{\pi}{3}\\\\288^o=\dfrac{288\pi}{180}=\dfrac{8\pi}{5}\qquad\dfrac{18\pi}{5}=2\pi+\dfrac{8\pi}{5}=\dfrac{8\pi}{5}\\\\315^o=\dfrac{315\pi}{180}=\dfrac{7\pi}{4}\qquad\dfrac{23\pi}{4}=4\pi+\dfrac{7\pi}{4}=\dfrac{7\pi}{4}\\\\80^o=\dfrac{80\pi}{180}=\dfrac{4\pi}{9}\qquad\dfrac{22\pi}{9}=2\pi+\dfrac{4\pi}{9}=\dfrac{4\pi}{9}$

8 0

4 years ago

Read 2 more answers