In a group of 50 students 38 play chess and 24 play scrabble. How many plays both chess and scrabble.

Mathematics

1 answer:

Grace [21]2 years ago

4 0

Answer:

Solve:

to solve, first add both partial numbers together

38 + 24 = 62

then subtract the whole number

62 - 50 = 12

Step-by-step explanation:

the way this works is the overflow when adding the two numbers, is the amount of students that do both, they count in both groups meaning their counted twice, this means that if each student dropped a coin for what they played (1 for chess and/or 1 for scrabble) the 12 students who played both would drop two coins

not a professional explanation but i hope it makes sense ^^

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What is the approximate value of b, rounded to the nearest tenth? Use the law of sines to find the answer. Law of sines: answers

Dominik [7]

Answer:

$\boxed{\text{2. 4.7 units}}$

Step-by-step explanation:

Assume your triangle has the dimensions shown below.

Before we can use the Law of Sines, we must find ∠C.

1. Calculate ∠C

$\begin{array}{rcl}A + B + C & = & 180^{\circ}\\66^{\circ} + 76^{\circ} + C & = & 180^{\circ}\\142^{\circ} + C & = & 180^{\circ}\\C & = & 38\, ^{\circ}\\\end{array}$

2. Calculate b

Use the Law of Sines

$\begin{array}{rcl}\dfrac{b}{\sin B } & = & \dfrac{c}{\sin C}\\\\\dfrac{b}{\sin 76^{\circ}} & = & \dfrac{3}{\sin 38^{\circ}}\\\\\dfrac{b}{0.9703} & = & \dfrac{3}{0.6157}\\\\ & = & 4.873\\b & = & 0.9703\times 4.873\\& = & \boxed{\mathbf{4.7}}\\\end{array}$