A soap manufacturer advertises that it has increased the size of their bottle of dishwashing soap to 18.4 ounces, which is 5% mo
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Answer:
Margin of error = 4.21 ounces
Step-by-step explanation:
According to the Question,
- Given That, You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8 ounces
Therefore, Sample mean = 31 ounces , Sample size(n) = 25 , Alpha(α) = 0.10 & Population standard deviation(σ) = 12.8 ounces
- Thus, Margin of error =
× σ / √n (
Putting The Values, We get
1.645 × (12.8 / √25 ) ⇒ 4.2112 ≈ 4.21
Thus, the maximum margin of error associated with a 90% confidence interval for the true population mean turtle weight is 4.21 ounces
Answer:
Step-by-step explanation:
Use a slope form.
<u>Slope:</u>
y₂ = (17)
y₁ = (1)
x₂ = (2)
x₁ = (-2)
Then, rewrite the problem.
Solve.
Therefore, the slope is 4, which is our answer.
I hope this helps you! Let me know if my answer is wrong or not.