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crimeas [40]
2 years ago
10

Find the sum of 6a - 5b + c, -2a +4b -2c​

Mathematics
1 answer:
Sphinxa [80]2 years ago
4 0

Answer:

4a-b-c

Step-by-step explanation:

we first look at the letters of each number. if there is only a letter, there is an imaginary 1 in front of it. we need to make sure that we add the numbers that have the exact same letters because they are known as like terms. we cannot add 6a and 4b because the letters are different and they are known as unlike terms. When we add numbers with the same letter ONLY the number changes

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The quotient of a number and 2 is the same as the difference of the number double and 3. What’s is the numer
Brums [2.3K]

\dfrac{x}{2}=2x-3\\ x=4x-6\\ 3x=6\\ x=2

8 0
3 years ago
Bradbury scar caught 35 fish with his net 20 percent of the fish had to be thrown back into the sea because they were too small
Lerok [7]
7 fish were thrown back
6 0
2 years ago
Chevy has some yarn that he wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each sc
Rashid [163]

Answer:

The system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.

Step-by-step explanation:

Let number of hat Chevy makes be h.

Also Let number of scarves Chevy makes be s.

Given:

Total Amount of yarns = 2 kg

Total number of items = 15

Since Items need to make are hat and scarves.

Hence the equation can be represented as;

h+s=15 \ \ \ \ equation \ 1

Again Given:

Each hat uses 0.2 kilograms of yarn.

each scarf uses 0.1 kilograms of yarn.

Hence the equation can be represented as;

0.2h+0.1s=2 \ \ \ \ \ equation \ 2

Hence the system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Now Solving these to find number of hats and number of scarves.

Multiplying equation 2 with 10 we get;

10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3

Now Subtracting equation 1 from equation 3 we get;

(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5

Now Substituting the value of h in equation 1 we get;

h+s= 15\\5+s =15\\s=15-5\\s=10

Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.

5 0
3 years ago
Jordan throws a ball from a cliff 12 feet above the ground with an initial velocity of 32 feet per second. In the following func
lbvjy [14]

Answer:

Your answer will be the third function

Step-by-step explanation:

The base function you need to know is h(t)= 1/2at^2

Your acceleration in this problem is going to be gravity which they give to you, 32 feet per second squared. Since the ball is falling, it means it will have negative acceleration. Now you have the equation h(t)= -16t^2. The final step is to add the initial height from which the ball was dropped giving you: h(t)= -16t^2 +12

8 0
2 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
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