Answer:
To attain
➠The value of √27*√3
Solution
➠
![\sqrt{27} \times \sqrt{3 } \\ = > \sqrt{81} \\ = > 9](https://tex.z-dn.net/?f=%20%5Csqrt%7B27%7D%20%20%5Ctimes%20%20%5Csqrt%7B3%20%7D%20%20%5C%5C%20%20%3D%20%20%3E%20%20%5Csqrt%7B81%7D%20%20%5C%5C%20%20%3D%20%20%3E%209)
Hence, 9 is the resulting Value for √27*√3
<span>Answer B
If the sum of the digits in the number is a multiple of the number 9 is divisible by 9
A 63
digits : 6,3
sum 6 + 3 = 9
9 : 9 = 1
</span><span>The number of 63 is divisible by 9
</span>.............................................................
B 69
digits 6,9
sum 6 + 9 = 15
1,(6)
------------
15 : 9
- 9
----------
60
- 54
--------
60
<span>the number 69 is not a multiple of 9 and divided by 9 do not receive natural number</span>........................................................
C 18
digits 1,8
sum 1+8 = 9
9:9 = 1
<span>The number of 63 is divisible by 9
</span>........................................................
D 27
digits 2,7
sum 2 + 7 = 9
9 : 9 = 1
<span>The number of 63 is divisible by 9
</span>............................................................
difficult
621450450
digits 6,2,1,4,5,0,4,5,0
1 sum 6 + 2 + 1 + 4 + 5 + 0 + 4 + 5 + 0 = 27
2 sum 2 + 7 = 9
9 : 9 = 1
<span>The number of 63 is divisible by 9
</span>
621450450 :9 = 69050050
Answer:
See explanations
Step-by-step explanation:
We have only one equation which is:
![y = 3x + 2](https://tex.z-dn.net/?f=y%20%3D%203x%20%2B%202)
The number of equation is 1.
This means that, there are infinitely many solutions to the given equation.
To find a solution, we choose a value for x, substitute it into the equation and then solve for y.
For instance, when x=0, we have:
![y = 3(0) + 2](https://tex.z-dn.net/?f=y%20%3D%203%280%29%20%2B%202)
![y = 0 + 2 = 2](https://tex.z-dn.net/?f=y%20%3D%200%20%2B%202%20%3D%202)
Therefore (0,2) is one of the solutions.
Answer:
I don't know
Step-by-step explanation:
my previous answer was wrong
I honestly don’t know but thanks for the points