Surface Area of the figure is 1208 square centimeters
a=20
b=13
c=12
d=5
e=8
Top face:
A1=a×e=20×8
ae=160
Bottom face:
A2(a+2d)×e=(20+2×5)×8=(20+10)×8=30×8
(a+2d)e=240
Front face:
Rectangle
a×c=20×12=240
Triangle:
12c×d=12×12×5=6×5=30
A3Rectangle +2 triangles
240+2×30=240+60=300
(a+d)c=300
Slant face:
A4=b×e=13×8=104
be=104
Total surface area
A=A1+A2+2(A3+A4)
A1=160
A2=240
A3=300
A4=104
Thus,
A=160+240+2(300+104)
A=400+2(404)
A=400+808=1208
Surface Area of the figure is 1208 square centimeters
The equation of the line with slope m and passing through the point 
is
Since m=6 and the coordinates of the point are (8,3), then the equation is
Answer: correct choice is B.
Answer:
s > 62
Step-by-step explanation:
- Write it out: s - (-31) > 93
- Simplify: s + 31 > 93
- Subtract 31 from each side, so it now looks like this: s > 62
I hope this helps!
