Answer:
50 tickets with a meal and 20 tickets without a meal
Step-by-step explanation:
Create two equations. Group the information based on labels. All the amounts that have $ in it go with one equation and the number of tickets will be in the second equation.
I will let x represent with a meal and y will represent without a meal
35x + 25y = 2250
x + y = 70
I will solve using substitution, so I will solve for y in the second equation. To do this, I will subtract x from both sides.
x - x + y = 70 - x
y = 70 - x
Now I will substitute in for y in the first equation and solve for x.
35x + 25(70 - x) = 2250
35x + 1750 - 25x = 2250
10x + 1750 = 2250
10x + 1750 - 1750 = 2250 - 1750
10x = 500
10x/10 = 500/10
x = 50
Now I will solve for y. I will use the original second equation and substitute 50 in for x.
x + y = 70
50 + y = 70
50 - 50 + y = 70 -50
y = 20
50 tickets with a meal and 20 tickets without a meal
