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kondor19780726 [428]
2 years ago
5

Susanna walked 2/7 of a mile in two over five of an hour what is a unit rate in miles per hour

Mathematics
2 answers:
Aleks [24]2 years ago
8 0

Answer:

speed = distance/ time so:

(2/7) / (2/5) = (2/7) x (5/2) = 10/14 = 5/7 mph

5/7 = 0.71 miles per hour if you need decimal formatStep-by-step explanation:

9966 [12]2 years ago
4 0

Step-by-step explanation:

2/7 miles in 2/5 hours.

to bring this to x miles / 1 hour, we must find the factor for 2/5 to turn into 1.

2/5 × f = 1

f = 5/2

in order to keep the value of the original ratio, we now need to multiply also 2/7 by the same factor (5/2).

2/7 × 5/2 = 10/14 = 5/7

so, the unit rate is 5/7 miles / hour.

which is very slow walking.

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Telephone plan consist of a monthly fee of $20 plus $.20 per minute for long distance calls made write an equation for the total
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Answer:

C=20+0.20N

Step-by-step explanation:

Fixed monthly fee = $20

Amount charged per minute for long distance calls = $0.20

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1. ) 1 thru 9 are both natural numbers and whole numbers. 0 is a whole number, but not a natural number.

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3 years ago
Hey! I'v been struggling with this question lately. Can someone just lend me a hand?
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So, this problem is asking us to find the value of our variable u. 

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The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

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So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

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We calculate the value of A using the initial condition P(0)=100, substituting t=0:

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