Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

By substitution:

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

Zero Product Property:

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
-3.4, -1.5, 0, 1/2, 8.5, and 8.45
Hope this helped:))
In order the numbers are 20, 29, 32, 37, 42.
So that means the median is 32. In order for the median to stay the same one of the three data values must be 32 as well as adding a number to each side of the ends. One 32 or less another 32or more.
The mean right now is: 20+29+32+37+42=160 and there are 5 values.
Mean: 160/5=32
For it to increase by 10 it has to be 42.
extra 3 numbers I used were 31, 32, & 113 (those are your answer)
Answer:
<h2>7.4inches</h2>
Step-by-step explanation:
Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.
According to the rule;

Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

The length of u is 7.4inches to nearest 10th of an inch
I believe the answer would be 150.75 cm as Marks height. I got this by if Bradley is the tallest, he would be 152.0 and if Calvin is taller than Josh, who is the shortest, the only height left would be Marks at 150.75