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telo118 [61]
2 years ago
9

In a programming team of 16 persons, 1/4 are women and 3/4 are men. To obtain a team with 40 percent women, how many women shoul

d be hired
Mathematics
1 answer:
brilliants [131]2 years ago
5 0

Answer:

4 more woman. total women in the team = 8 women

Step-by-step explanation:

1/4 * 16 = 4 women and 16 - 4 = 12 men

8/20  * 100 = 40%

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Please help me :> i would love that ! :))
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Answer:

The total is 90%

Step-by-step explanation:

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3 years ago
If Logan(3)=5, what is the value of a^5?​
Archy [21]

Answer:

  a^5=3

Step-by-step explanation:

When it comes to exponential expressions and logarithms, the following relationship applies:

  \log_b{(x)}=a\ \leftrightarrow\ b^a=x

Here, it means ...

  \boxed{a^5=3}

8 0
3 years ago
Read 2 more answers
Please help asap, will mark Brainliest xoxo
IgorC [24]

Answer/Step-by-step explanation:

Given, b(x) = (\frac{6}{7})^{x}

The table for the function are:

When x = -2

b(-2) = (\frac{6}{7})^{-2}

b(-2) = \frac{1}{(\frac{6}{7})^{2}}

b(-2) = \frac{1}{(\frac{36}{49})}

b(-2) = 1*\frac{49}{36}

b(-2) = \frac{49}{36}

When x = -1

b(-1) = (\frac{6}{7})^{-1}

b(-1) = \frac{1}{(\frac{6}{7})}

b(-1) = 1*\frac{7}{6}

b(-2) = \frac{7}{6}

When x = 0

b(0) = (\frac{6}{7})^{0}

b(0) = \frac{6^0}{7^0}

b(0) = \frac{1}{1}

b(0) = 1

When x = 1

b(1) = (\frac{6}{7})^{1}

b(1) = \frac{6}{7}

When x = 2

b(2) = (\frac{6}{7})^{2}

b(2) = \frac{6^2}{7^2}

b(2) = \frac{36}{49}

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3 years ago
Find the coordinate of the circumcenter of the triangle with the vertices:
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5.8333, -1.8333 I think
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Water is leaking from the bottom of a canonical cup that is 6 inches across and 8 inches deep. Given that the cup loses 0.9 inch
DochEvi [55]
6 inches AND IT HADS UP TO 4.69 INCHES

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3 years ago
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