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eimsori [14]
3 years ago
5

Given that f(x)=x^2+3x+6 and g(x)= x-3/2, solve for f(g(x)) when x=1

Mathematics
1 answer:
podryga [215]3 years ago
4 0
If you would like to solve for f(g(x)) when x = 1, you can do this using the following steps:

<span>f(x) = x^2 - 3x + 6
g(x) = x - 3/2

f(g(x)) = f(</span>x - 3/2) = (x - 3/2)^2 - 3 * (x - 3/2) + 6
x = 1
f(g(1)) = f(1 - 3/2)  = f(-1/2) = (-1/2)^2 - 3 * (-1/2) + 6 = 1/4 + 3/2 + 6 = 1/4 + 6/4 + 24/4 = 31/4 = 7 3/4

The correct result would be 7 3/4. add me as a friend 
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Step-by-step explanation:

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Niki wants to buy a dog bed the cost $87. She earns $6 per week for doing chores. How many weeks will Niki have to do her chores
Viktor [21]

Answer:

The answer to your question is 14.5 weeks

Step-by-step explanation:

Data

Total cost = C = $87

money earned = m = $6

Number of weeks to have the money = w = ?

Process

1.- Write an equation that represents the situation

            Weeks = Total cost / Money earned

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2.- Substitute the values

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3.- Result

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4.- Conclusion

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2 years ago
I’m completely lost can anybody help solve this
Marizza181 [45]

Answer:

\huge\boxed{x=54^o}

Step-by-step explanation:

<em>Look at the picture.</em>

<em />

We have:

l=108^o

Therefore

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\dfrac{2\alpha}{2}=\dfrac{108^o}{2}\\\\\alpha=54^o

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It is A! I know because i just took the test!
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Read 2 more answers
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