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2 years ago

GIVING BRAINLIEST

Mathematics

1 answer:

Arte-miy333 [17]2 years ago

8 0

Answer:

i dont know

Step-by-step explanation:

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What is the volume of this triangular prism? 313.6cm3 506.8cm3 5,676.16cm3 11,352.32cm3

lyudmila [28]

The question is incomplete. Here is the complete question:

What is the volume of this triangular prism?

Base length = 22.4 cm

Height = 18.1 cm

Length = 28 cm

A) 313.6 cm3

B) 506.8 cm3

C) 5,676.16 cm3

D) 11,352.32 cm3

Answer:

$V=5,676.16\ cm^3$

Step-by-step explanation:

Given:

The base of the prism is triangular with base length equal to 22.4 cm and height 18.1 cm. The length of the prism is 28 cm.

The volume of a triangular prism is defined by the formula:

$V=(Area\ of\ base)\times (length)$

Here, the base is triangular and the area of a triangle is:

$A=\frac{1}{2}base \times height$

Therefore, the volume of the triangular prism is given as:

$V=\frac{1}{2}(base\times height\times length)$

Now, plug in the given values and solve for the volume 'V'.

$V=\frac{1}{2}(22.4\ cm\times 18.1\ cm\times 28\ cm)\\\\V=\frac{1}{2}(11,352.32\ cm^3)\\\\V=5,676.16\ cm^3$

Therefore, the correct answer is the third option.

$V=5,676.16\ cm^3$

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Given that 8x – 4y = 39<br>Find y when x = 5

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8(5) - 4y = 39
40 - 4y = 39
-4y = -1, y = 1/4
Solution: y = 1/4

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There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model

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$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill$

$A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}$

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