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2 years ago

3c=3HELPP PLEASE NEED HELPPPP

Mathematics

2 answers:

scoundrel [369]2 years ago

6 0

Divide the 3 from the 3c, and move over towards the 3 on the right side of the equation. 3 ÷ 3 = 1, so c = 1.

liberstina [14]2 years ago

5 0

You're working with variables. Since the operation is multiplication (a number next to a variable signals multiplication) you do the inverse, or opposite, and divide that by three. The three will cancel it out, but if you divide by three there, you have to do it on the other side. Three divided by three is one!

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2 years ago

BRAINLIEST AND 15 POINTS

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Answer:

Step-by-step explanation:

You will need to measure five different people. Record your measurements on a piece of paper. Using a tape measure or ruler, measure the length (in inches) of a persons left foot and then measure the length (in inches) of that same persons forearm (between their wrist and elbow). Refer to the diagrams below. You will have two measurements for each person. (An easy way to measure the length of a foot is to have your subject stand on a piece of paper. Then, trace their foot and measure the outline once they move off the paper.) To measure the forearm, measure inside the arm, between the wrist and the elbow. Part 2 Organize your data and find the rate of change. Create a table of the measurements for your data. Label the forearm measurements as your input and the foot measurements as your output. Select two sets of points and find the rate of change for your data. Describe your results. If you had to express this relation as a verbal statement, how would you describe it? Part 3 Compare rates of change. The equation below can be used to find the length of a foot or forearm when you know one or the other. (length of the foot) = 0.860 (length of the forearm) + 3.302 If you let y = length of the foot and x = length of the forearm, this equation can be simplified to y = 0.860x + 3.302. Using this equation, how long would the foot of a person be if his forearm was 17 inches long? What is the rate of change of the equation from Part A? Compare the equation from Part A to your data. Are they the same? Which has a greater rate of change? Why do you think the values are different? Is the relation in your data a function? Why or why not? Could the equation in Part A represent a function? Why or why not? Explain your answer. For this option you will submit the details from all three parts. Submit your measurements, the table, and description that you created in Parts 1 and 2. Submit your answers to the questions from Part 3

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2 years ago

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

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2 years ago