Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
i have answers but im not sure if there correct but ill write them down anyway a.6 b.2,3,6,9 c.first of all its spelled dice not die and yes because it all equals 100:)
Answer: 4
Step-by-step explanation:
Perpendicular lines have reciprocal slopes
Answer:
29
Step-by-step explanation:
Put x=0 into the function and do the arithmetic.
h(0) = 29(5.2)^0 = 29(1)
h(0) = 29 . . . . the y-intercept
