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3 years ago

Something times something that equals 7

Mathematics

2 answers:

iogann1982 [59]3 years ago

8 0

You can only do 1 times 7 or 7 times 7. (Same thing, just different order)

Anestetic [448]3 years ago

3 0

Well since two solid numbers cant make 7 I would do 3.5 x 7

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Solve this quadratic equation using the quadratic formula. 2x 2 - 10x + 7 = 0

sladkih [1.3K]

Answer:X=11/10

Step-by-step explanation:

2x2-10x+7=0

4-10x+7=0

11-10x=0

-10x= -11

Divide both side by -10

-10x/-10. -11/-10

Answer= 11/10

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3 years ago

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Write whether the scenario represents a linear function or an exponential function? Explain why.

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The scenario represents a linear function. The rate is at a constant increase therefore it is linear.

Linear because it’s a constant rate

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2 years ago

Simplify each expression -21v^6/-6v^8, v=0

EleoNora [17]

Answer:

The correct answer is,

$- \frac{7v {14}^{} }{2}$

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3 years ago

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The diagram shows 3 identical circles inside a rectangle.

Ilya [14]

Answer:

11700 mm²

Step-by-step explanation:

A rectangle is a quadrilateral with two equal, opposite and parallel sides. Each of the angles in a rectangle is 90°.

The horizontal distance of the rectangle = r + r + r + r = 4r

The vertical distance = r + h + r = 2r + h

Where h is the distance between the midpoint of the 2 up circles and the midpoint of the down circle.

Using Pythagoras:

(2r)² = h² + r²

h² + r² = 4r²

h² = 3r²

h = √3r²

h = r√3

Vertical distance = 2r + h = 2r + r√3

Area of rectangle = vertical distance * horizontal distance

Area = 4r * (2r + r√3) = 8r² + 4r²√3 = 4r²(2 + √3)

Substituting:

Area = 4r²(2 + √3) = 4(28²)(2 + √3) = 11703.711 mm²

Area = 11700 mm² to 3 s.f

5 0

2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

Hence, the amount of oil was decreasing at 69300 barrels, yearly

7 0

2 years ago