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3 years ago

How does cot(x)sin(x)=cos^3(x)+cos(x)sin^2(x)?

Mathematics

1 answer:

Svetllana [295]3 years ago

5 0

$\cot(x)\sin(x)=\cos^3(x)+\cos(x)\sin^2(x)$

$R=\cos(x)[\cos^2(x)+\sin^2(x)]=\cos(x)\cdot1=\cos(x)\\\\L=\dfrac{\cos(x)}{\sin(x)}\cdot\sin(x)=\cos(x)\\\\L=R\\\\\text{used:}\\\\\sin^2x+\cos^2x=1\\\\\cot x=\dfrac{\cos x}{\sin x}$

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Amanda, Rafael, and Michael served a total of 92 orders Monday at the school cafeteria. Rafael served 2 times as many orders as

Schach [20]

The number of orders Michael, Rafael and Amanda served are 16.8, 33.6, and 41.6 servings

respectively.

<h3>Equation</h3>

Michael = x
Rafael = 2x
Amanda = 2x + 8
Total servings = 92 orders

x + 2x + (2x + 8) = 92

3x + 2x + 8 = 92

5x = 92 - 8

5x = 84

x = 84/5

x = 16.8 servings

Therefore,

Michael = x

= 16.8 servings

Rafael = 2x

= 2(16.8)

= 33.6 servings

Amanda = 2x + 8

= 33.6 + 8

= 41.6 servings

Learn more about equation:

brainly.com/question/4344214

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1 year ago

The value of y varies directly with x and y 8 when x 2 find y when x 10 answer

Zielflug [23.3K]

8:2=4:1 Answer y=40
hope this helps.

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3 years ago

What is the measure of angle RST?<br> a. 87<br> b. 131<br> c. 93<br> d. 90

shtirl [24]

Answer: C

Step-by-step explanation:

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3 years ago

What is the opposite of 5.98

Liono4ka [1.6K]

Answer:

$\huge\boxed{-5.98}$

Step-by-step explanation:

The opposite of 5.98 is the negative one.

Since 5.98 is a positive integer, it's opposite would be the negative integer having a "-" sign.

<u>So, the opposite of 5.98 is:</u>

=> -5.98

4 0

2 years ago

Read 2 more answers

The temperature, H, in °F, of a cup of coffee t hours after it is set out to cool is given by the following equation. H = 70 + 1

Alex73 [517]

Answer:

The temperature a t = 0 is 190 °F

The temperature a t = 1 is 100 °F

The temperature a t = 2 is 77.5 °F

It takes 1.5 hours to take the coffee to cool down to 85°F

It takes 2.293 hours to take the coffee to cool down to 75°F

Step-by-step explanation:

We know that the temperature in °F, of a cup of coffee t hours after it is set out to cool is given by the following equation:

$H(t)=70+120(\frac{1}{4})^t$

a) To find the temperature a t = 0 you need to replace the time in the equation:

$H(0)=70+120(\frac{1}{4})^0\\H(0)=70+120\cdot 1\\H(0) = 70+120\\H(0)=190 \:\°F$

b) To find the temperature after 1 hour you need to:

$H(1)=70+120(\frac{1}{4})^1\\H(1)=70+120(\frac{1}{4})\\H(1) = 70+30\\H(1)=100 \:\°F$

c) To find the temperature after 2 hours you need to:

$H(2)=70+120(\frac{1}{4})^2\\H(2)=70+120(\frac{1}{16})\\H(2) = 70+\frac{15}{2} \\H(2)=77.5 \:\°F$

d) To find the time to take the coffee to cool down $85 \:\°F$ , you need to:

$85 = 70+120(\frac{1}{4})^t\\70+120\left(\frac{1}{4}\right)^t=85\\70+120\left(\frac{1}{4}\right)^t-70=85-70\\120\left(\frac{1}{4}\right)^t=15\\\frac{120\left(\frac{1}{4}\right)^t}{120}=\frac{15}{120}\\\left(\frac{1}{4}\right)^t=\frac{1}{8}$

$\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)$

$\ln \left(\left(\frac{1}{4}\right)^t\right)=\ln \left(\frac{1}{8}\right)$

$\mathrm{Apply\:log\:rule}=\log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$t\ln \left(\frac{1}{4}\right)=\ln \left(\frac{1}{8}\right)$

$t=\frac{\ln \left(\frac{1}{8}\right)}{\ln \left(\frac{1}{4}\right)}\\t=\frac{3}{2} = 1.5 \:hours$

e) To find the time to take the coffee to cool down $75 \:\°F$ , you need to:

$75=70+120\left(\frac{1}{4}\right)^t\\70+120\left(\frac{1}{4}\right)^t=75\\70+120\left(\frac{1}{4}\right)^t-70=75-70\\120\left(\frac{1}{4}\right)^t=5\\\left(\frac{1}{4}\right)^t=\frac{1}{24}$

$\ln \left(\left(\frac{1}{4}\right)^t\right)=\ln \left(\frac{1}{24}\right)\\t\ln \left(\frac{1}{4}\right)=\ln \left(\frac{1}{24}\right)\\t=\frac{\ln \left(24\right)}{2\ln \left(2\right)} \approx = 2.293 \:hours$

3 0

3 years ago