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ella [17]
3 years ago
5

How does cot(x)sin(x)=cos^3(x)+cos(x)sin^2(x)?

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

\cot(x)\sin(x)=\cos^3(x)+\cos(x)\sin^2(x)

R=\cos(x)[\cos^2(x)+\sin^2(x)]=\cos(x)\cdot1=\cos(x)\\\\L=\dfrac{\cos(x)}{\sin(x)}\cdot\sin(x)=\cos(x)\\\\L=R\\\\\text{used:}\\\\\sin^2x+\cos^2x=1\\\\\cot x=\dfrac{\cos x}{\sin x}

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