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ella [17]
3 years ago
5

How does cot(x)sin(x)=cos^3(x)+cos(x)sin^2(x)?

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

\cot(x)\sin(x)=\cos^3(x)+\cos(x)\sin^2(x)

R=\cos(x)[\cos^2(x)+\sin^2(x)]=\cos(x)\cdot1=\cos(x)\\\\L=\dfrac{\cos(x)}{\sin(x)}\cdot\sin(x)=\cos(x)\\\\L=R\\\\\text{used:}\\\\\sin^2x+\cos^2x=1\\\\\cot x=\dfrac{\cos x}{\sin x}

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PLEASE HELP ME!<br> Drag the expressions into the boxes to correctly complete the table.
Kamila [148]

<em><u>The polynomials are:</u></em>

x^4+3x^3-5x^2-7x+20

x^3-2x^2+x-12

x^2+3x^5-6x+12x^3

<em><u>Not a polynomial are:</u></em>

4\sqrt[3]{x} -\sqrt{x}  -20

\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40

x^{-3}-x^{-2}-6x^{-1}+8

<em><u>Solution:</u></em>

Polynomial is an expression with variables and coefficients,

Which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables

<em><u>Option 1</u></em>

4\sqrt[3]{x} -\sqrt{x}  -20

Polynomial does not include roots

This is not a polynomial equation

<em><u>Option 2</u></em>

x^4+3x^3-5x^2-7x+20

This is polynomial expression involving addition and subtraction between terms with non-negative integer exponents of variables

<em><u>Option 3</u></em>

\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40

This is not a polynomial. This equations involves negative integer exponents of variables

<em><u>Option 4</u></em>

x^3-2x^2+x-12

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

<em><u>Option 5</u></em>

x^{-3}-x^{-2}-6x^{-1}+8

This is not a polynomial. This equations involves negative integer exponents of variables

<em><u>Option 6</u></em>

x^2+3x^5-6x+12x^3

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

5 0
3 years ago
For the graphed function f(x) = (4)x − 1 + 2, calculate the average rate of change from x = 1 to x = 2.
xz_007 [3.2K]
For the function
  f(x) = 4^(x-1) +2
the average rate of change on the interval [1, 2] is found by computing
  (f(2) - f(1))/(2 - 1)
  = ((4^1+2) - (4^0+2)/1
  = (6-3)
  = 3
3 0
3 years ago
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bulgar [2K]
Helloooo each day she picked 13 tomatoes

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