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Mama L [17]
4 years ago
10

PLEASE HELP!!! THIS IS DUE SOON

Mathematics
1 answer:
Hoochie [10]4 years ago
7 0

Answer:

It's 65

Step-by-step explanation:

The reason is because the whole thing needs to be 180 right.

So one of the sides is 67

D would have to be 65 because of the angle and also it is less then F.

E is 48 because it is cut.

So the answer would be 65

I hope this helps!

Please mark me brainliest

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A)16x^2+24x+9=(4x)^2+2*4x*3+3^2=(4x+3)^2\\


B)4x^2-49y^2=(2x)^2-(7y)^2=(2x-7y)(2x+7y)
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4 years ago
How to do area for 6th grade
Alexxx [7]

To find the area of a square is Base x Height.

Triangle is 1/2 base x height.

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4 years ago
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. For which of the sample sizes wou
chubhunter [2.5K]

Answer:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

Step-by-step explanation:

For this case we know that for a random variable X we have the following parameters given:

\mu = 102, \sigma =10

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

8 0
3 years ago
https://lh3.googleusercontent.com/ZdagxxHvwERtpsxOHZwM5NSZgCwMCHN2KfRNp_BgcaHunkEAgxWxtlnBy9Kzw8sjh7CIuND8lTho9_dQLeH1AgXynwP1ro
DanielleElmas [232]

What am I supposed to do?

8 0
4 years ago
Read 2 more answers
Question 5(Multiple Choice Worth 1 points)
Anit [1.1K]

Answer:

x+3x+5=101 (Option C).

Step-by-step explanation:

This question requires to be solved using the supposition method.

Let Aylen's savings be $x. Therefore, Rich's savings would be $(3x+5). This is because it is mentioned that Rich has $5 more than 3 times the amount of money Aylen has. The sum of the savings is $101. Therefore the sum of the savings of Aylen and Rich is given by:

x + 3x + 5 = 101. Thus, Option C is the correct answer.

Solve the equation for x gives x = $24. This is Aylen's share. To calculate Rich's share, simply put x=24 in 3x+5. Thus, Rich's share will be $77.

In short, Rich's share = $77, Alan's share = $24, and this has been calculated using the equation x+3x+5=101 (Option C)!!!

8 0
4 years ago
Read 2 more answers
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