2sinxcosx - sin(2x)cos(2x) = 0
<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>
<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>
<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>
<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>
<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>
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Answer:
Step-by-step explanation:
t = 158 Corresponding angles
t + s = 180 They are supplementary angles
158 + s = 180 Subtract 158 from both sides
s = 180 - 158
s = 22
As a note, all angles in this situation are either 158 or 22.
Answer:
k = 3
Step-by-step explanation:
If the line passing through the points A (-1,3k) and B (k , 3) is parallel to the line whose equation is 2y+3x=9, then their slopes are equal
For coordinate AB;
slope m1 = 3 - 3k/k-(-1)
m1 = 3-3k/k+1
For the line 2y+3x = 9
2y = -3x + 9
y = -3/2 x + 9/2
Slope m2 = -3/2
Since m1 = m2
3-3k/k+1 = -3/2
Cross multiply
2(3-3k) = -3(k+1)
Expand
6 - 6k = -3k - 3
-6k+3k = -3 - 6
-3k = -9
k = -9/-3
k = 3
Hence the value of k is 3
Answer:
ummm I think this is obvious
Step-by-step explanation:
2 circles in each group, shade in one group of 2.
