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3 years ago

What is the answer to 18.7 and 18.6 rounding to the nearest tenth

Mathematics

1 answer:

aivan3 [116]3 years ago

8 0

187=190 186=190 because 18.7 and 18.6 are 187 and 186 so 8 is the tenth place. So they both equal 190

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If 15x+17*2=227 what is x

sladkih [1.3K]

X will be 35 but idk the formula

8 0

2 years ago

Plz help its so confusing

aleksklad [387]

Answer:

20, 4

Step-by-step explanation:

Let's assume total number of students registered is n

Last week n/4 people are absent

so people present are n - n/4 = 3n/4

Today after return of Jen 1/5 n are absent

so people present are n - n/5 = 4n/5

which is also equal to last week present people + 1 (Jen)

= 3n/4 + 1

= (3n + 4) / 4

so (3n + 4) / 4 = 4n/5

=> 3n + 4 = 4n/5 * 4

=> (3n + 4) * 5 = 16n

=> 15n + 20 = 16n

=> 20 = n

=> n = 20

So total students registered for class is 20

today no of people absent = n/5 = 20/5 = 4

8 0

2 years ago

Show work ! please !!!!!!

Law Incorporation [45]

Sin A = opp/hyp = 4/5

Cos A = adj/hyp = 3/5

Tan A = opp/adj = 4/3

Cos 27 = 0.8910065... --> 0.89

You can just plug that into your graphing calculator, just make sure the degree mode is on.

3 0

2 years ago

Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest

Len [333]

The annual rate of interest per year is 8%

Solution:

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440 – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

$\text {Simple Interest }=\frac{P \times R \times T}{100}$

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

$1840=\frac{4600 \times R \times 5}{100}$

$\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}$

Hence, the required rate of interest per year is 8%

6 0

3 years ago

PLEASE HELP

Vlad [161]

Do you need the answer now ?

3 0

2 years ago