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2 years ago

Solve 8m-2(14-m)>7(m-4)+3m

Mathematics

1 answer:

emmasim [6.3K]2 years ago

5 0

Answer:

0>0 or error

Step-by-step explanation:

8m-2(14-m)>7(m-4)+3m

8m-28+2m>7m-28+3m

10m-28>10m-28

0>0

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PLEASE HHELP!!! Bring the fraction:

Anna35 [415]

Answer:

$\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}$

$\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}$

Step-by-step explanation:

Given

$\frac{b}{7a^2c}$

Express the denominator as $35a^3c^3$

To do this, we divide $35a^3c^3$ by the denominator

$\frac{35a^3c^3}{7a^2c} = 5ac^2$

So, the required fraction is:

$\frac{b}{7a^2c} * \frac{5ac^2}{5ac^2}$

$\frac{5abc^2}{35a^3c^3}$

Hence:

$\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}$

Given

$\frac{a}{a - 4}$

Express the denominator as $16 - a^2$

Multiply the fraction a+4/a+4

So, we have:

$\frac{a}{a - 4} * \frac{(a + 4)}{(a + 4)}$

Apply difference of two squares to the denominator

$\frac{a^2 + 4a}{a^2 - 16}$

Take the additive inverse of the numerator and denominator

$\frac{-(a^2 + 4a)}{-(a^2 - 16)}$

$\frac{-a^2 - 4a}{16 -a^2}$

Hence:

$\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}$

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2 years ago

What is the equation of the line (in slope-intercept form) that passes through the point (5,−1) and is parallel to the line y=2x

tatyana61 [14]

Answer:

Step-by-step explanation:

$\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\===============================$

$\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\\\==========================$

$\text{We have the equation of a line:}\ y=2x-7\to m_1=2.\\\\\text{The slope of a parallel line:}\ m_2=m_1=2.\\\\\text{We have the equation:}\\\\y=2x+b\\\\\text{Put the coordinates of the point (5, -1) o the equation:}\\\\-1=2(5)+b\\-1=10+b\qquad\tex\text{subtract 10 from both sides}\\-11=b\to b=-11\\\\\text{Finally:}\\\\y=2x-11$

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3 years ago

Help!!!<br> Find the zeros of the quadratic equation by factoring.<br><br> x^2+4x-5=0

weqwewe [10]

Answer:

x = -5, 1

Step-by-step explanation:

To factor an equation, break the polynomial into two binomials which multiply to make it. Find two numbers that multiply to C and add to B from $ax^2 + bx + c$ .

-1 and 5 multiply to -5 and add to 4.

$x^2+4x-5 = (x+5)(x-1)$

The zeros are the factors set equal to 0 and solved.

(x+5) = 0

x=-5

(x-1) = 0

x=1

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3 years ago