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Ainat [17]
3 years ago
6

How do you use the additive inverse to evaluate an expression that uses subtraction ?

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0
Additive inverse is the negative of the number, i.e. what you add to the number to get zero.

So the additive inverse of number b is - b

Additive inverse of 4 is - 4.

Then, you can verify the subtraction is the same that add the additive inverse.

For example subtracting 4 from 10 (10 - 4) is the same that adding -4:

10 - 4 = 10 + (-4).

Then given any expression if you have to subtract other expressión you just add the addive inverse of the second expression.

For example: given A(x) = x^2 + 3x + 5 and B(x) = 2x + 4

Find A(x) - B(x) = A(x) + [-B(x)]

=> x^2 + 3x + 5 + (-2x -4) = x^2 + 3x - 2x + 5 - 4 = x^2 + x + 1

Sergio039 [100]3 years ago
5 0

Answer:

Change the expression from subtraction to addition. Take the opposite of the second integer. Rewrite the expression with addition and the additive inverse, and solve.

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Step-by-step explanation:

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Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

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