(y-x) (2+3)= (yx)(5)
But am not sure it could be =(2-3) (y+x) = (1) (yx)
I’m sorru but there’s nothing there
Answer:
I guess that You made a mistake and You wanted to solve equations ![\sqrt[2]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7By%7D)
. Then the answer is D because There is no number that gives a negative number after the square root
Step-by-step explanation:
Answer: 62
Step by step: sorry !!
Not really sure what you are looking for, but this is how to solve equations such as these.
Let:
x = number of pounds of granola
y = numer of pounds of walnuts
The equation he can use to compute the total cost would be:
$2.00x + $6.00y = $12.00
We know that he bought 3 pounds of granola, so we plug in that for the x value:
$2.00(3) + $6.00y = $12.00
$6.00 + $6.00y = $12.00
To isolate the unknown value which is y, we first need to subtract $6.00 from both sides of the equation:
$6.00 + $6.00y - $6.00 = $12.00 - $6.00
$6.00y = $6.00
Then we divide both sides by $6.00:
$6.00y/$6.00 = $6.00/$6.00
y = 1
So the number of bags of walnuts he can buy is 1 bag.
