Hello from MrBillDoesMath!
Answer: 48.2 degrees
Discussion:
In the diagram, "6" is the x- distance along the side adjacent to theta, and
3 * sqrt(5) is the y-distance along the side opposite angle theta.
By definition of tangent of angle, using "@" for theta, we have
tan (@) = opposite/adjacent = 3 * sqrt(5) / 6 = sqrt(5)/2
So @ = (inverse tangent (sqrt(5)/2) ) = 48.189 degrees (approximately)
Thank you,
MrB
Answer:
35°
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relationship between trig functions and sides of a right triangle. The pole and its shadow form the legs of the right triangle with the side adjacent to the angle of elevation being the shadow. "TOA" tells you ...
Tan = Opposite/Adjacent
tan(elevation angle) = (pole height)/(shadow length)
tan(elevation angle) = 35/50 = 0.7
The inverse tangent function, arctan( ) or tan⁻¹( ), is used to find the angle from the value of its tangent.
elevation angle = arctan(0.7) ≈ 34.99° ≈ 35°
The value is given in question.... put the corresponding value in the equation in place of "x" and you will obtain the value of "y"
Answer:
<h2>C) PA = PB</h2>
Step-by-step explanation:
AB = PB + PA
PC is the perpendicular bisects of the segment BA.
Therefore PB = PA → AB = 2PB = 2PA → PB = PA = 1/2AB.
