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Alex73 [517]
4 years ago
15

Billy gas two books he gave to two of his friends got one book how much books does billy have left

Mathematics
2 answers:
zalisa [80]4 years ago
8 0
Billy would have 1 book left. Hope this helps!
Lina20 [59]4 years ago
4 0
He has 0 books left.
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A combination lock requires three numbers from 1 to 25. how many combinations are possible? did you use the sum rule or the prod
maria [59]
Combinations possible = 25 * 25 * 25. Product rule

The point is that numbers can be reused. 1 5 1 is a valid combination as is   4 4 4 

20 * 5 * 1 is a valid combination as is 1 25 5

So the answer is 15625 "combinations" are possible <<<<< answer
7 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
never [62]

Answer:

3

Step-by-step explanation:

3 0
4 years ago
The ratio of the loudness of lala's earphones to the loudness of polina's earphones to the loudness of goffy's earphones is 6:5:
tresset_1 [31]
Let:
Lala be l
Polina be P
Goffy be G
the respective ratio is 6:5:3
Given that Polina's loudness is 420 decibels then the total loudness will be calculated as follows:
Total ratio=6+5+3=14
hence total loudness will be:
14/5×420
=1,176 decibels 
3 0
3 years ago
What is the y-intercept of the line perpendicular to the line y = 3/4x + 3 that includes the point (-3, -3)
kipiarov [429]
A perpendicular line has an opposite reciprocal slope. This means that the new line will have a slope of -4/3x. Plug in x and y into the equation y=Mx +b where m is the slope (-4/3):
-3=(-3/4)(-3) + b
and isolate b:
b-3=(-3/4)(-3)
b=(-3/4)(-3) +3
b=9/4+3
b=21/4

The final equation is y= -4/3x + 21/4
The y intercept is (21/4).
6 0
3 years ago
Find an equation of the sphere with center (4, −12, 8) and radius 10.
Lorico [155]

Answer:

Step-by-step explanation:

To find an equation of the sphere with center (4, −12, 8) and radius 10

(x-4)^2+(y+12)^2+(z-8)^2 = 100

intersection with xy-plane

Put z=0

(x-4)^2+(y+12)^2+(0-8)^2 = 100

(x-4)^2+(y+12)^2 = 36

(A circle with centre at (4,-12) and radius 6)

intersection with xz-plane

Put y =0

(x-4)^2+(0+12)^2+(z-8)^2 = 100

(x-4)^2+(z-8)^2 = -44

Sum of squares cannot be positive, so DNE

intersection with yz-plane

Put x=0

(0-4)^2+(y+12)^2+(z-8)^2 = 100

(y+12)^2+(z-8)^2 = 84

A circle in YZ plane with centre at y =-12 and z =8 and radius square root of 84

5 0
3 years ago
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