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Serhud [2]
3 years ago
8

Can someone help me answer this​

Mathematics
2 answers:
marishachu [46]3 years ago
8 0
Ok done. Thank to me :>

slamgirl [31]3 years ago
5 0

32^{-\tfrac 25}\\\\=(2^5)^{-\tfrac 25}\\\\=2^{-2}\\\\=\dfrac 1{2^2}\\\\=\dfrac 14

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Solve the equation for all values of x in simplest form (x + 3)^2 = -16
Arlecino [84]

Answer:

x = -7 or  x = 1

Step-by-step explanation:

Given expression:

    (x + 3)²  = -16

 

Problem;

   Solve for x;

Solution:

 To solve for x; we use the factorization method;

     Take -16 to the left of the equation;

      (x + 3)²  = -16

         (x + 3)² + 16 = 0

       (x+ 3)² + 4²  = 0

if    x² + y²  = (x + y)(x - y)

     So;

       (x + 3 + 4) (x + 3 - 4) = 0

       (x + 7)(x - 1) = 0

       x + 7  = 0 or x - 1 = 0

      x = -7 or  x = 1

6 0
3 years ago
The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia
KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}

The values of the cumulative distribution function of W, denoted by \phi , can be found in the attached file. Lets call y = \frac{z-70}{4} . We have

0.1 = P(X > z) = P(\frac{X-70}{4} > \frac{z-70}{4}) = P(W > y) = 1-\phi(y)

Thus

\phi(y) = 1-0.1 = 0.9

by looking at the table, we find that y = 1.28, therefore

\frac{z-70}{4} = 1.28\\z = 1.28*4+70 = 75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

Download pdf
8 0
3 years ago
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