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Crazy boy [7]
2 years ago
14

Robin donated bags of grain that each weighed 40/3 pounds to the local food shelf. If the total weight of the grain was 160 poun

ds, how many bags of grain did Robin donate?
A. 4
B. 6
C. 8
D. 12
Mathematics
1 answer:
Novay_Z [31]2 years ago
7 0

Answer:

d 12

Step-by-step explanation:

You might be interested in
.Find the Z-sCore corresponding to the given value and use the z-SCore to determine whether the value is unusual. Consider a sco
sertanlavr [38]

Answer:

d. -1.9; not unusual

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that;

X = 50, \mu = 69, \sigma = 10.

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 69}{10}

Z = -1.9

A z-score of -1.9 is higher than -2 and lower than 2, so it is not unusual.

So the correct answer is:

d. -1.9; not unusual

5 0
3 years ago
56. How many tangent lines to the curve <img src="https://tex.z-dn.net/?f=y%3Dx%20%2F%28x%2B1%29" id="TexFormula1" title="y=x /(
PIT_PIT [208]

There are 2 tangent lines that pass through the point

y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2

and

y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2

Explanation:

Given:

y=\frac{x}{x+1}

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:

y=m(x-1)+2 [1]

For the lines to be tangent to the curve, we must substitute the first derivative of the curve for m:

\frac{dy}{dx} =\frac{d(x)}{dx}(x+1)-x^\frac{d(x+1)}{dx} \\ \\

\frac{dy}{dx} =\frac{x+1-x}{(x+1)^2}

\frac{dy}{dx}= \frac{1}{(x+1)^2}

m=\frac{1}{(x+1)^2} [2]

Substitute equation [2] into equation [1]:

y=\frac{x-1}{(x+1)^2}+2 [1.1]

Because the line must touch the curve, we may substitute y=\frac{x}{x+1}:

\frac{x}{x+1}=\frac{x-1}{(x+1)^2}+2

Solve for x:

x(x+1)=(x-1)+2(x+1)^2

x^2+x=x-1+2x^2+4x+2

x^2+4x+1

x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}

x=-2 ± \sqrt{3}

x=-2 ± \sqrt{3}<em> </em>and x=-2-\sqrt{3}

There are 2 tangent lines.

y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2

and

y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2

8 0
2 years ago
You have a small bag of candy-coated chocolates that melt in our mouth; three are red, four are yellow, tow are green, and five
DerKrebs [107]
Red- 3
yellow- 4
green- 2
blue- 5
= 14 all together

green- 2/14, 1/7, or 14%
blue- 5/14, or 36%

I don't know what you mean by eat it
4 0
3 years ago
The point (0, 4) is located
Doss [256]

Answer:

it would be on y-4.

and there is no x coordinate because it's 0

3 0
2 years ago
PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
andrezito [222]

Answer:

1 Spanish  90%

2.French 37%

3. Chinese  18%

Step-by-step explanation:

9/10 ..........    90/100 ...........   90%

37%..................           37%

9/50.............            18/100 ..........  18%

4 0
3 years ago
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