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2 years ago

14

Robin donated bags of grain that each weighed 40/3 pounds to the local food shelf. If the total weight of the grain was 160 poun

ds, how many bags of grain did Robin donate?
A. 4
B. 6
C. 8
D. 12

1 answer:

Novay_Z [31]2 years ago

7 0

Answer:

d 12

Step-by-step explanation:

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.Find the Z-sCore corresponding to the given value and use the z-SCore to determine whether the value is unusual. Consider a sco

sertanlavr [38]

Answer:

d. -1.9; not unusual

Step-by-step explanation:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that;

$X = 50, \mu = 69, \sigma = 10$ .

So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{50 - 69}{10}$

$Z = -1.9$

A z-score of -1.9 is higher than -2 and lower than 2, so it is not unusual.

So the correct answer is:

d. -1.9; not unusual

5 0

3 years ago

56. How many tangent lines to the curve <img src="https://tex.z-dn.net/?f=y%3Dx%20%2F%28x%2B1%29" id="TexFormula1" title="y=x /(

PIT_PIT [208]

There are 2 tangent lines that pass through the point

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

Explanation:

Given:

$y=\frac{x}{x+1}$

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:

$y=m(x-1)+2$ $[1]$

For the lines to be tangent to the curve, we must substitute the first derivative of the curve for $m$ :

$\frac{dy}{dx} =\frac{d(x)}{dx}(x+1)-x^\frac{d(x+1)}{dx} \\ \\$

$\frac{dy}{dx} =\frac{x+1-x}{(x+1)^2}$

$\frac{dy}{dx}= \frac{1}{(x+1)^2}$

$m=\frac{1}{(x+1)^2}$ $[2]$

Substitute equation [2] into equation [1]:

$y=\frac{x-1}{(x+1)^2}+2$ $[1.1]$

Because the line must touch the curve, we may substitute $y=\frac{x}{x+1}:$

$\frac{x}{x+1}=\frac{x-1}{(x+1)^2}+2$

Solve for x:

$x(x+1)=(x-1)+2(x+1)^2$

$x^2+x=x-1+2x^2+4x+2$

$x^2+4x+1$

$x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}$

$x=-2$ ± $\sqrt{3}$

$x=-2$ ± $\sqrt{3}$ <em> </em> $and$ $x=-2-\sqrt{3}$

There are 2 tangent lines.

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

8 0

2 years ago

You have a small bag of candy-coated chocolates that melt in our mouth; three are red, four are yellow, tow are green, and five

DerKrebs [107]

Red- 3
yellow- 4
green- 2
blue- 5
= 14 all together

green- 2/14, 1/7, or 14%
blue- 5/14, or 36%

I don't know what you mean by eat it

4 0

3 years ago

The point (0, 4) is located

Doss [256]

Answer:

it would be on y-4.

and there is no x coordinate because it's 0

3 0

2 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

andrezito [222]

Answer:

1 Spanish 90%

2.French 37%

3. Chinese 18%

Step-by-step explanation:

9/10 .......... 90/100 ........... 90%

37%.................. 37%

9/50............. 18/100 .......... 18%

4 0

3 years ago