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Lana71 [14]
2 years ago
8

During development individual cells of the same organism begin to produce different proteins because.

SAT
1 answer:
Ira Lisetskai [31]2 years ago
4 0

Answer:

The cell types in a multicellular organism become different from one another because they synthesize and accumulate different sets of RNA and protein molecules. They generally do this without altering the sequence of their DNA.

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Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM
Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

<em>#include <cmath></em>

<em>#include "pppm_tip4p.h"</em>

<em>#include "atom.h"</em>

<em>#include "domain.h"</em>

<em>#include "force.h"</em>

<em>#include "memory.h"</em>

<em>#include "error.h"</em>

<em>#include "math_const.h"</em>

<em />

<em>using namespace LAMMPS_NS;</em>

<em>using namespace MathConst;</em>

<em />

<em>#define OFFSET 16384</em>

<em />

<em>#ifdef FFT_SINGLE</em>

<em>#define ZEROF 0.0f</em>

<em>#define ONEF  1.0f</em>

<em>#else</em>

<em>#define ZEROF 0.0</em>

<em>#define ONEF  1.0</em>

<em>#endif</em>

<em />

<em>void PPPMTIP4P::init()</em>

<em>{</em>

<em>  // TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms</em>

<em />

<em>  if (force->newton == 0)</em>

<em>    error->all(FLERR,"Kspace style pppm/tip4p requires newton on");</em>

<em />

<em>  PPPM::init();</em>

<em>}</em>

<em />

<em>void PPPMTIP4P::particle_map()</em>

<em>{</em>

<em>  int nx,ny,nz,iH1,iH2;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))</em>

<em>    error->one(FLERR,"Non-numeric box dimensions - simulation unstable");</em>

<em />

<em>  int flag = 0;</em>

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;</em>

<em>    ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;</em>

<em>    nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;</em>

<em />

<em>    part2grid[i][0] = nx;</em>

<em>    part2grid[i][1] = ny;</em>

<em>    part2grid[i][2] = nz;</em>

<em />

<em>    if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||</em>

<em>        ny+nlower < nylo_out || ny+nupper > nyhi_out ||</em>

<em>        nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;</em>

<em>  }</em>

<em />

<em>  int flag_all;</em>

<em>  MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);</em>

<em>  if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");</em>

<em>}</em>

<em>void PPPMTIP4P::make_rho()</em>

<em>{</em>

<em>  int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;</em>

<em>  FFT_SCALAR dx,dy,dz,x0,y0,z0;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];</em>

<em>  for (i = 0; i < ngrid; i++) vec[i] = ZEROF;</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double *q = atom->q;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = part2grid[i][0];</em>

<em>    ny = part2grid[i][1];</em>

<em>    nz = part2grid[i][2];</em>

<em>    dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;</em>

<em>    dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;</em>

<em>    dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;</em>

<em />

<em>    compute_rho1d(dx,dy,dz);</em>

<em />

<em>    z0 = delvolinv * q[i];</em>

<em>    for (n = nlower; n <= nupper; n++) {</em>

<em>      mz = n+nz;</em>

<em>      y0 = z0*rho1d[2][n];</em>

<em>      for (m = nlower; m <= nupper; m++) {</em>

<em>        my = m+ny;</em>

<em>        x0 = y0*rho1d[1][m];</em>

<em>        for (l = nlower; l <= nupper; l++) {</em>

<em>          mx = l+nx;</em>

<em>          density_brick[mz][my][mx] += x0*rho1d[0][l];</em>

<em>        }</em>

<em>      }</em>

<em>    }</em>

<em>  }</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

6 0
2 years ago
A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times. Let x¯1 represent the average of the
SIZIF [17.4K]

The sampling distribution of the difference in sample means x⁻₁ - x⁻₂ is; 3.5 - 3.5 = 0

<h3>Difference in sample means</h3>

We are told that;

  • A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times.
  • x⁻₁ represents the average of the first ten rolls.
  • x⁻₂ represents the average of the remaining five rolls.

Now, the average of the largest and lowest numbers of the six sided die is;

E(x) = (6 + 1)/2 = 3.5

Thus, the average mean of the first ten rows is expressed as;

E(x⁻₁) = (n * E(x))/n

E(x⁻₁) = (10 * 3.5)/10

E(x⁻₁) = 3.5

The average mean of the last five rolls will be;

E(x⁻₂) = (n * E(x))/n

E(x⁻₂) = (5 * 3.5)/5

E(x⁻₂) = 3.5

Thus;

x⁻₁ - x⁻₂ = 3.5 - 3.5 = 0

Read more about difference in sample means at; brainly.com/question/16428987

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What is another way to say "where a function crosses the x-axis"?
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X-intercept, zero, root.. all of the above!
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Which statement best describes dickon's character in the secret garden?.
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Explanation:

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​The answer is: Enforcing anti dicsrimination laws

Responsibilities refers to the things that a person or an organization must do regardless of their preferene. (following the constituiton would be a responsibility to all citizens without any exception)

Distributing federal funding, operates the school,  and determining the type of curriculum should be made is what we referred to as 'rights' , not responsibilities.

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