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2 years ago

A hot-air balloon is 1550 feet off the ground and its altitude is slowly changing at a constant rate of −712 feet per second.

2 answers:

5 0

Building and solving an equation to model the situation, it is found that it will take 1.52 seconds for the balloon to drop to below 465 feet.

The initial height is of 1550 feet.

Each second, the height decreases by 712 feet.

Hence, the equation that models the height of the balloon after t seconds is:

$h(t) = 1550 - 712t$

To find how many seconds, s, will it take for the balloon to drop to below 465 feet, we have to find <u>t for which h(t) < 465</u>, hence:

$h(t) < 465$

$1550 - 712t < 465$

$712t > 1085$

$t > \frac{1085}{712}$

$t > 1.52$

It will take 1.52 seconds for the balloon to drop to below 465 feet.

A similar problem is given at brainly.com/question/25290003

balu736 [363]2 years ago

4 0

Answer:

s > 144 2/3

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

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$Z = \frac{X - \mu}{\sigma}$

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