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NeTakaya
3 years ago
8

A hot-air balloon is 1550 feet off the ground and its altitude is slowly changing at a constant rate of −712 feet per second.

Mathematics
2 answers:
stiks02 [169]3 years ago
5 0

Building and solving an equation to model the situation, it is found that it will take 1.52 seconds for the balloon to drop to below 465 feet.

  • The initial height is of 1550 feet.
  • Each second, the height decreases by 712 feet.

Hence, the equation that models the height of the balloon after t seconds is:

h(t) = 1550 - 712t

To find how many seconds, s, will it take for the balloon to drop to below 465 feet, we have to find <u>t for which h(t) < 465</u>, hence:

h(t) < 465

1550 - 712t < 465

712t > 1085

t > \frac{1085}{712}

t > 1.52

It will take 1.52 seconds for the balloon to drop to below 465 feet.

A similar problem is given at brainly.com/question/25290003

balu736 [363]3 years ago
4 0

Answer:

s > 144 2/3

Step-by-step explanation:

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