How can I find slope

1 answer:

5 0

To find the slope of a line, you first chooses 2 points with known coordinates that belongs to the line. Let those points be A(x1,y1) and B(x2,y2) with x2>x1. You then divide the subtraction of their Ys as y2-y1 by the subtractions of their Xs as x2-x1 (the point with the higher x comes first, this is why x2>x1). And let the slope be m. m= (y2-y1) / (x2-x1). If the slope is positive, the line croissant and y2>y1. If the slope is negative, the line is decroissant and y1>y2. Hope this helps! :)

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Consider this sequence

pochemuha

Hello,

$u_{1} =1*(8-7)=1*(2*4-(6+1))\\
 u_{2} =2*(10-7)=2*(2*5-(6+2))=2*(2*(4+1)-(6+2))\\
 u_{3} =3*(12-9)=3*(2*6-(6+3))=3*(2*(4+2)-(6+3))\\
 u_{4} =4*(14-10)=4*(2*7-(6+4))=4*(2*(4+3)-(6+4))\\

$

$u_{10}=10*(2*(4+10)-(6+10))\\
=10*(28-16)
$

$...\\\\
u_{n} =n*(2*(n+n-1)-(6+n))\\
=n*(4n-2-6-n)=n(3n-8)\\

$

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<h2>Answer: </h2>

We know that,

Length of arc = 2πrθ/360

Length of arc = 2 × 3.14 × 6 × 45/360

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