Answer:
I most likely think it is approximately 19%
Step-by-step explanation:
Assuming you mean still receive an allowance even though they dont do chores:
Ok In all the total number of students is 21. Out of those 21, 4 still receive an allowance even though they dont do chores. This is 4/21. Now all we have to do is convert 4/21 into a percentage. To do this we have to divide 100 by 21, then times 4 by that number:
100 / 21 = >> approximately 4.76
Now 4 times 4.76 :
4 * 4.76 = >>> approximately 19.04 % . We round it to 19%.
So the answer is 19%.
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now,
We know that the sum of probability of an event and its complement is 1.
So,
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
7/4
4 goes into 7 one time.
3 left over.
1 3/4
Answer:
Just from looking at the picture, I'm assuming that we're trying to find the terms that are like to the terms in the blue section.
1. 8c since both are in terms of c
2. 7t since both are in terms of t
3. 8r since both are in terms of r
4. -4n since both are in terms of n
5. xy since both are in terms of xy
6. 16 since both don't have any variables
7. 4sp since both are in terms of sp
Step-by-step explanation: