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maks197457 [2]
3 years ago
12

A car rental company charges, y, for x, days. Days 3 4 5 6

Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

The equation of the car rental company in the form y = kx is; y = 18.50x

The equation y = kx is such that;

  • y = dependent variable

  • x = independent variable

  • k = constant of proportionality.

In essence; to determine the constant of proportionality, k in this case;

  • k = y/x

Since the company charges, $55.50 for 3 days; we have;

By evaluation k = $55.50/3

  • k = 18.50.

A constant rate of change means the variation in the dependent variable as dependent on the independent variable is constant

Read more:

brainly.com/question/19012756

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Four students equally share 1\4 poud of peanuts.How of a pound of peanuts did each student get?
posledela

Answer:1/16

Step-by-step explanation:1/4= .25

Divide .25 by 4( for the four students) = .0625

.0625 is equivalent to 1/16

4 0
2 years ago
For an outdoor concert by the city orchestra, concert organizers estimate that 10,000 people will attend if it's not raining. If
Vlada [557]

Answer:

The number of expected people at the concert is 8,500 people

Step-by-step explanation:

In this question, we are asked to determine the expected number of people that will attend a concert if we are given the probabilities that it will rain and it will not rain.

We proceed as follows;

The probability that it will rain is 30% or 0:3

The probability that it will not rain would be 1 -0.3 = 0.7

Now, we proceed to calculate the number of people that will attend by multiplying the probabilities by the expected number of people when it rains and when it does not rain.

Mathematically this is;

Number of expected guests = (probability of not raining * number of expected guests when it does not rain) + (probability of raining * number of expected guests when it rains)

Let’s plug values;

Number of expected guests = (0.3 * 5,000) + (0.7 * 10,000) = 1,500 + 7,000 = 8,500 people

4 0
3 years ago
What is the answer to this question?<br> Y=x^2-1 with the input as 5
mixas84 [53]

We can see that, when the input is 5, the output is 24.

<h3>How to evaluate an equation?</h3>

Here we have the equation:

y = x^2 - 1

Where y is the output and x is the input.

We want to evaluate it with the input as 5, so we need to replace the variable x by the number 5, we will get:

y = 5^2 - 1 = 24

Then we can see that, when the input is 5, the output is 24.

If you want to learn more about evaluating functions:

brainly.com/question/1719822

#SPJ1

4 0
2 years ago
Which of the following equations has the same solution as m-(-62) = 45?
prisoha [69]

Answer:

answer 45

Step-by-step explanation:

it is thr right answe

5 0
3 years ago
Read 2 more answers
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
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