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3 years ago

15

If 32^2c = 8^c+7, what is the value of c? 0 1 O2 O 3 05

2 answers:

lidiya [134]3 years ago

8 0

Answer:

32^ 2c=8^ c+7

C=3

sweet [91]3 years ago

8 0

The answer would be choice 3

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Dan saved 463 over 12 weeks of summer break.he saaved 297 of it during the last 4 weeks .how much did he save during the first 8

Rainbow [258]

The answer is 166. I subtracted 463 - 297 = 166
he saved 166 during the first 8 weeks!

4 0

3 years ago

Jeremy ran 5 yards 2 feet 3 inches. In the same time, John ran 9 yards 1 foot 10 inches. How many inches farther did John run th

m_a_m_a [10]

5 yards 2 feet 3 inches:
1 yard=36 inches; 5 yards=180 inches
1 foot=12 inches; 2 feet=24 inches
180+24+3=207 inches

9 yards 1 foot 10 inches:
9 yards=324 inches
1 foot=12 inches
324+12+10=346 inches
346-207=139 inches
John ran 139 inches fartheer than Jeremy

5 0

4 years ago

Read 2 more answers

Write an equation in slope-intercept form that passes through (-6,-2) and had a y-intercept located at y=-5

valina [46]

Answer:

(-6, -2) is the answer

Step-by-step explanation:

8 0

3 years ago

Jim is enclosing a rectangular garden with 170 feet of fencing. The length of the garden is 10 feet more than twice it’s width,

Darina [25.2K]

Answer:

$1,500\ ft^2$

Step-by-step explanation:

Let

L ----> the length of the rectangular garden in feet

w ---> the width of the rectangular garden in feet

step 1

Find the width

we know that

The perimeter of the rectangular garden is

$P=2(L+W)$

$P=170\ ft$

so

$170=2(L+W)$

Simplify

$85=(L+W)$ ----> equation A

$L=2W+10$ ----> equation B

substitute equation B in equation A and solve for W

$85=(2W+10+W)$

$85-10=3W$

$3W=75$

$W=25\ ft$

Find the value of L

$L=2(25)+10=60\ ft$

step 2

Find the area

we know that

The area of the rectangular garden is

$A=(LW)$

substitute the values

$A=(60)(25)=1,500\ ft^2$

6 0

3 years ago

Please need help asap!

beks73 [17]

Answer:

66

Step-by-step explanation:

(z-33)/z = 1/2

2z-66=z

z=66

6 0

3 years ago