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2 years ago

Which inequality is true when x = 4?

Mathematics

1 answer:

elena-s [515]2 years ago

7 0

Answer:

x + 5 < 3

Step-by-step explanation:

One inequality could be x > 3. So when x = 4 this is true because 4 is greater than 3.

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A sum of $4200 was invested, part at 8% and the remainder at 11%. If $426.00 was earned in interest after one year, how much was

enot [183]

Answer:

$3000 was invested at 11%.

Step-by-step explanation:

The total interest was $426. This was comprised of interest earned at 8% (represented by e) and (separately) interest earned at 11% (represented by v).

Then e + v = $4200 total investment, and

i = $426 = e(0.08)(1 year) + v(0.11)(1 year)

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i = $426 = ($4200 - v)(0.08)(1 year) + v(0.11)(1 year)

This is one equation in one unknown, the amount of $ invested at 11%.

Performing the indicated multiplications:

426 = 4200(0.08) - 0.08v + 0.11v. Simplifying this further, we get:

426 = 336 + 0.03v.

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$3000 was invested at 11%.

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3 years ago

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Dmitrij [34]

Answer:

$V=9\pi\sqrt{3}$

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

$V=\int\limits^b_a {\pi r^{2}} \, dy$